Answer:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.
Explanation:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.
Answer:
yes This is correct Answer
Answer:
Magnitude = 3.64 ×
စ = 43.9°
Explanation:
given data
ship to travel = 1.7 ×
kilometers
turn = 70°
travel an additional = 2.7 ×
kilometers
solution
we will consider here
Px = 1.7 ×
Py = 0
Qx =2.7 ×
cos(70)
Qy= 2.7 ×
sin(70)
so that
Hx = Px + Qx ............1
Hx = 2.62 ×
and
Hy = Py + Qy ..........2
Hy = 2.53 ×
so Magnitude = 
Magnitude = 3.64 ×
so direction will be
tan စ = Hy ÷ Hx ......................3
tan စ =
tan စ = 0.9656
စ = 43.9°
Answer:
The horizontal force is 106.89 N.
Explanation:
Given that,
Work done = 310 J
Distance = 2.9 m
We need to calculate the horizontal force
Using formula of work done

Where, 

Put the value into the formula



Hence, The horizontal force is 106.89 N.