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Kobotan [32]
3 years ago
13

The velocity of a wave is the product of the frequency and the

Physics
2 answers:
Amiraneli [1.4K]3 years ago
7 0

Answer:

option A

Explanation:

Velocity = Wavelength / Time

But we know that Frequency = 1 / Time. So ,

Velocity = Wavelength × Frequency

Nuetrik [128]3 years ago
6 0

Answer:

The answer is A. wavelength

Based on the wavespeed formula v=fλ

Velocity of wave is the product of <em>frequency(f)</em> and <em>wavelength(λ)</em>

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Communication with submerged submarines via radio waves is difficult because seawater is conductive and absorbselectromagnetic wa
FrozenT [24]

Answer:

D. 4000 km

Explanation:

f = Frequency of wave that is being transmitted = 76 Hz

\lambda = Wavelength of wave that is being transmitted

v = The velocity of electromagnetic waves through air = 3\times 10^8\ m/s

Velocity of a wave is given by

v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{3\times 10^8}{76}\\\Rightarrow \lambda=3947368.42105\ m=3947.36842105 km\approx 4000\ km

Hence, the approximate wavelength of the waves is 4000 km

8 0
3 years ago
What is the kind of energy that comes from movement?
Sergio [31]

Answer:

motion energy

Explanation:

motion wnergy is the sum of potential and kinetic energy

4 0
3 years ago
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A car speedometer has a 4% uncertainty. What is the range of possible speeds (in km/h) when it reads 110 km/h?
Kruka [31]
4% of 110 is 4.4. So the possible range of speeds is the interval from 110-4.4 till 110+4.4.
105.6 till 114.4
4 0
3 years ago
2.5 g of helium at an initial temperature of 300 K interacts thermally with 9.0 g of oxygen at an initial temperature of 620 K .
muminat

Answer:

Explanation:

2.5 g of He = 2.5 / 4  mole

= .625 moles

9 g of oxygen = 9/32

= .28 mole of oxygen

C_p of He = 3/2 R

C_p of O₂ = 5/2 R

A ) Initial thermal energy of He = 3/2 n R T

= 1.5 x .625 x 8.32 x 300

= 2340 J

Initial thermal energy of O₂ = 5/2 n R T

= 2.5 x .28 x 8.32 x 620

= 3610.88 J

B ) If T be the equilibrium temperature after mixing

gain of heat by helium

= n C_p Δ T

= .625 x 3/2 R x ( T - 300 )

Loss of heat by oxygen

n C_p Δ T

= .28 x 5/2 R x ( 620 - T )

Loss of heat = gain of heat

.625 x 3/2 R x ( T - 300 ) = .28 x 5/2 R x ( 620 - T )

1.875 T- 562.5 = 868- 1.4 T

3.275 T = 1430,5

T = 436.8 K

Thermal energy of He

= 1.5 x .625 x 8.32 x 436.8

= 3407 J

thermal energy of O₂

= 2.5 x .28  x 8.32 x 436.8

= 2543.92 J

C )

Heat energy transferred

=  .28 x 5/2 R x ( 620 - T )

=  .28 x 5/2 x  8.32 x ( 620 - 436.8 )

1066.95 J

Heat will flow from O₂ to He

Final temperature is 436.8 K

7 0
3 years ago
Which of the following is a good thermal insulator?*<br> Iron<br> Styrofoam<br> Silver<br> Graphite
Goryan [66]

Answer: graphite

Explanation:

7 0
3 years ago
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