Arcsin or sin^-1
Hope this helps!
Answer: A BaBr2
Explanation:
On the left side of the equation, the superscript 2 is applied to both sodium AND bromine. That means you need 2 bromine on the right. Also on the left side, the 2 AFTER chlorine only applies to the chlorine so there’s only one barium. What you have on the left has to balance with what you have on the right.
Answer:
5.01×10⁴ J.
Explanation:
Applying,
q = Cm....................... Equation 1
Where q = amount of heat needed to melt the ice, m = mass of the ice, C = specific latent heat of ice.
From the question,
Given: m = 150 g = (150/1000) kg = 0.15 kg, C = 3.34×10⁵ J/kg
Substitute these values into equation 1
q = (0.15×3.34×10⁵)
q = 0.501×10⁵ J
q = 5.01×10⁴ J.
To rearrange these for v and r we must use BEDMAS.
First, times both sides by r, getting Ar = v²r/r
You can cancel out r/r to get Ar = v²
To get v, square root both sides. √Ar = √v²
Cancel out the square root and the squared v = √Ar
To get r, go back to Ar = v², then divide both sides by A. rA/A = v²/A
Then cancel out A/A to get r. r = v²/A
PART A)
Electrostatic potential at the position of origin is given by
here we have
now we have
Now work done to move another charge from infinite to origin is given by
here we will have
so there is no work required to move an electron from infinite to origin
PART B)
Initial potential energy of electron
Now we know
now by energy conservation we will have
So here initial total energy is sufficient high to reach the origin
PART C)
It will reach the origin