Answer:
7.71 × 10⁻⁴ M/s
Explanation:
The initial rate of the reaction can be expressed by using the formula:
![\dfrac{\Delta [O_2]}{\Delta t}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5CDelta%20%5BO_2%5D%7D%7B%5CDelta%20t%7D)
where the number of moles of O₂ = 
where;
Pressue P = 1.00 atm
Volume V =5.74mL = (5.74 /1000) L
Rate R = 0.082 L atm/mol.K
Temperature = 298 K
= 2.35 × 10⁻⁴ mol
Δ[O₂] = 
Δ[O₂] = 
Δ[O₂] = 0.04626 M
The initial rate =
= 
= 7.71 × 10⁻⁴ M/s
Answer:
37.15 h.
Explanation:
- The decay of radioactive elements obeys first-order kinetics.
- For first-order reaction: <em>kt = lna/(a-x).</em>
where, k is the rate constant of the reaction <em>(k = 2.4 x 10⁻² h⁻¹)</em>.
t is the time of the reaction <em>(t = ??? day)</em>.
a is the initial concentration of nuclides <em>(a = 100 %)</em>.
(a-x) is the remaining concentration of nuclides <em>(a - x = 100% - 59% = 41.0 %)</em>.
<em>∴ kt = lna/(a-x)</em>
(2.4 x 10⁻² h⁻¹)(t) = ln(100.0%)/(41.0%).
(2.4 x 10⁻² h⁻¹)(t) = 0.8916.
<em>∴ t </em>= (0.8916)/(2.4 x 10⁻² h⁻¹) = <em>37.15 h.</em>
Answer:
B. Controlled variables
Explanation:
The Dependent sample t-test compares the mean score of measurements in one group to that of another other group. It mainly used when analyzing comparable sample units as it pairs repeatable observations within a time frame.
Controlled variables are factors that are not tested and remain constant. Some examples of controlled variables are temperature, pressure, volume etc
Answer:
Under high temperatures and low pressure, gases behave the most ideal.
Explanation:
Low pressure reduces the effect of the finite size of real particles by increasing the volume around each particle, and a high temperature gives enough kinetic energy to the particles to better overcome the attractions that exist between real particles. (Prevents sticking.)
In summary, real gases behave more like ideal gases when they are far away from a phase boundary, (condensation or freezing).
