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zhenek [66]
3 years ago
14

What is the molarity of a solution made by dissolving 50.0 g of HBr in enough water to make 600. mL of solution?

Chemistry
1 answer:
Minchanka [31]3 years ago
3 0

Answer:

1.03M

Explanation:

mass/molar mass = moles of solution

50 g / (80+1) = 0.617 mol HBr

molarity*volume = moles

M*0.600 L = 0.617 mol

M = 0.617/0.600 = 1.03 M

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Determine the energy of 1.70 mol of photons for each of the following kinds of light. (Assume three significant figures.)PART A
BabaBlast [244]

<u>Answer:</u>

<u>For A:</u> The energy of the given amount of photons for infrared radiation is 1.271\times 10^5J

<u>For B:</u> The energy of the given amount of photons for infrared radiation is 4.026\times 10^5J

<u>For C:</u> The energy of the given amount of photons for infrared radiation is 1.355\times 10^6J

<u>Explanation:</u>

The relationship between energy and frequency is given by Planck's equation, which is:

E=n\rimes N_A\times \frac{hc}{\lambda}        ......(1)

where,

h = Planck's constant  = 6.62\times 10^{-34}Js

E = energy of the light

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of light

N_A = Avogadro's number = 6.022\times 10^{23}

n = number of moles of photons = 1.70 moles

Conversion factor used:  1m=10^9nm

  • <u>For A:</u>

Wavelength of infrared radiation = 1600nm=1.6\times 10^6m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-6}}\\\\E=1.271\times 10^5J

Hence, the energy of the given amount of photons for infrared radiation is 1.271\times 10^5J

  • <u>For B:</u>

Wavelength of visible light = 505nm=5.05\times 10^7m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{5.05\times 10^{-7}}\\\\E=4.026\times 10^5J

Hence, the energy of the given amount of photons for infrared radiation is 4.026\times 10^5J

  • <u>For C:</u>

Wavelength of ultraviolet radiation = 150nm=1.5\times 10^7m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.5\times 10^{-7}}\\\\E=1.355\times 10^6J

Hence, the energy of the given amount of photons for infrared radiation is 1.355\times 10^6J

3 0
3 years ago
Which of the following is a limited quality item? Nail polish
kakasveta [241]

Answer: Nail polish and Lithium batteries are Limited quantity item.

Explanation:

5 0
2 years ago
When titanium (II) nitride forms an ionic compound, what is the chemical formula of the compound?
jek_recluse [69]

Answer:

When titanium (II) nitride forms an ionic compound, TiN is the chemical formula of the compound.

4 0
3 years ago
A sample of lead has the density of 58 g/mL and a mass of 15.2g, what is the volume of the lead?
torisob [31]

Answer:

0.26 ml

Explanation:

d = m/V

=> V = m/d = 15.2/58 = 0.26 ml

4 0
1 year ago
To what temperature must a sample of nitrogen at 27°C and 0.625 atm be taken so that it’s pressure becomes 1.125 atm at constant
Karo-lina-s [1.5K]

Answer:

The sample of nitrogen must be taken to 267 ^{0}\textrm{C}.

Explanation:

Let's assume nitrogen gas behaves ideally.

Here amount of nitrogen gas in both states remain constant.

So, in accordance with combined gas law for a given amount of an ideal gas in two different states:            \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively. V_{1} and V_{2} are initial and final volume respectively. T_{1} and T_{2} are initial and final temperature (in kelvin scale) respectively.

Here V_{1}=V_{2} , P_{1}=0.625atm , T_{1}=(273+27)K=300K and P_{2}=1.125atm

So T_{2}=\frac{P_{2}T_{1}}{P_{1}}=\frac{(1.125atm)\times (300K)}{(0.625atm)}=540K

540 K = (540-273) ^{0}\textrm{C} = 267 ^{0}\textrm{C}

So the sample of nitrogen must be taken to 267 ^{0}\textrm{C}.

8 0
3 years ago
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