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IrinaK [193]
3 years ago
5

A circular pizza has a diameter of 12 inches . a pizza in the center of the pan has a radius of 4 inches . how much of the pan i

s not covered by the pizza use 3.14 for pi
Mathematics
1 answer:
matrenka [14]3 years ago
7 0
I think its 4.28537832453 
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frez [133]
Answer: It would be y=2x.
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3 years ago
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Use The Divergence Theorem To Calculate The Surface Integral and Sis a sphere centered at the origin with a radius of 2. Confirm
marin [14]

Answer: hi your question is incomplete below is the complete question

Use the Divergence Theorem to calculate the surface integral S F dS   with F x y z = , , and S is a sphere centered at the origin with a radius of 2. Confirm your answer by computing the surface integral

answer : surface integral = 384/5 π

Step-by-step explanation:

Representing  the vector field as

F ( x, y , z ) = ( a^3 + y^3 ) + ( y^3 + z^3 ) + ( Z^3 + x^3 ) k

assuming the sphere ( s) with radius = 2 be centered at Origin of the vector field.

Hence the divergence will be represented as :

Attached below is the detailed solution

6 0
3 years ago
Help me yall this for me aint it.
aleksandrvk [35]

Answer:

20(4 + 5)

Step-by-step explanation:

GCF is just the biggest number each value can be divided by. Here, it's 20, so that goes outside of the parenthesis. Now, what can you multiply by 20 to get 80? 4, so that goes in the second box. What can you multiply by 20 to get 100? 5, so that goes in the last box. You can check your answer by doing 80 + 100 = 180; 20(9) = 180.

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3 years ago
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Solve the inequality. 22−2x<38 Which answer represents the solution set?
algol [13]

Answer:

x >-8

Step-by-step explanation:

22−2x<38

Subtract 22 from each side

22-22−2x<38-22

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Divide each side by -2, remembering to flip the inequality

-2x/-2 > 16/-2

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3 0
3 years ago
In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Cal
soldier1979 [14.2K]

Given that,

Sample size= 83

Mean number= 39.04

Standard deviation= 11.51

We know the critical t-value for  95% confidence interval which is equal to 1.989.

We also know the formula for confidence interval,

CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))

So, we have

CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)

CI= (39.04 - 2.513,39.04 + 2.513)

CI= (36.527,41.553)

Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).

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