Answer:
Percent yield of NaCl = 87.75 %
Explanation:
Data given
mass of sodium = 20.0 g
actual yield of Sodium chloride = 25 g
percent yield of sodium chloride = ?
Reaction Given:
NaOH + HCI --> NaCl + H₂O
Solution:
First we have to find theoretical yield.
So, Look at the reaction
NaOH + HCI ---------> NaCl + H₂O
1 mol 1 mol
As 1 mole of NaOH give 1 mole of NaCl
Convert moles to mass
molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
molar mass of NaCl = 23 +35.5 = 58.5 g/mol
Now
NaOH + HCI ---------> NaCl + H₂O
1 mol (40 g/mol) 1 mol (58.5 g/mol)
40 g 58.5 g
So 40 g of NaOH gives 58.5 g of NaCl so how many grams of Sodium chloride will be produced by 20 g of NaOH.
Apply Unity Formula
40 g of NaOH ≅ 58.5 g of NaCl
20 g of NaOH ≅ X g of NaCl
Do cross multiply
g of NaCl = 58.5 g x 20 g / 40 g
g of NaCl = 29.25 g
So the Theoretical yield of NaCl = 29.25 g
Now Find the percent yield of NaCl
Formula Used
percent yield = actual yield /theoretical yield x 100 %
Put value in the above formula
percent yield = 25 / 29.2 x 100 %
percent yield = 87.75 %
percent yield of NaCl = 87.75 %
