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padilas [110]
3 years ago
14

According to the Arrhenius concept, which of the following substances is NOT a base in aqueous solutionsA. NH3B. LiOHC. NaOHD. H

2OE. Ca(OH)2
Chemistry
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

NH₃ (Option A)

Explanation:

Arrhenius theory explained that the acids are the ones that have H⁺, either H in its formula. Following this, the bases are the ones that have OH⁻ , either OH and its formula.

It can be used only with compounds with H, or OH.

So the ammonia is not a base, as Arrhenius theory.

It is known that ammonia behaves as a weak base, but it does not have hydroxide ions that can yield to water

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AT 45.0 °C and a pressure of 9.9 kPa a sample of gas has a volume of
dolphi86 [110]

<em>the </em><em>new </em><em>volume </em><em>will </em><em>be </em><em>8</em><em>2</em><em>×</em><em>1</em><em>0</em><em>-</em><em>3</em><em> </em><em>L </em><em>or </em><em>0</em><em>.</em><em>0</em><em>0</em><em>8</em><em>2</em><em> </em><em>L</em>

8 0
3 years ago
using the equation 2h2+o2--&gt;2h2o if 192g of oxygen are produced how many grmas of hydrogen must react with it
Brilliant_brown [7]
Equation: 2H₂ + O₂ → 2H₂O

Now, Given mass of Oxygen = 192 g
Molar mass of Oxygen = 16 g/mol

No. of moles in Oxygen = 16/192 = 0.0833

Now, for every mole of Oxygen, 2 mole of Hydrogen will form, 
so, Number of moles of Hydrogen = 0.0833 * 2 = 0.167

Given mass = Number of Moles * Molar mass
Given mass = 0.167 * 2
m = 0.33 g

In short, Your Answer would be: 0.33 g

Hope this helps!
7 0
4 years ago
Read 2 more answers
What volume of water (solute) (d = 1.00 g/mL) should be added to 600. mL of ethanol (solvent, C2H5OH) in order to have a solutio
Ugo [173]

Answer: Volume of water to be added is 116 ml.

Explanation:

Elevation in boiling point is given by:

\Delta T_b=i\times K_b\times m

\Delta T_b=T_b-T_b^0=(95.0-78.4)^0C=16.6^0C = elevation in boiling point

i= vant hoff factor = 1 (for non electrolyte)

K_b =boiling point constant = 1.22^0C/m

m= molality

\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Density of solvent =\frac{\text {mass of solvent}}{\text {Volume of solvent}}

0.789g/ml=\frac{\text {mass of solvent(ethanol)}}{600ml}

{\text {mass of solvent(ethanol)}=473.4g=0.4734 kg    (1kg=1000g)

Mass of solute (water) = x g

16.6^0C=1\times 1.22\times \frac{x}{18g/mol\times 0.4734kg}

x=116g

Density of solute =\frac{\text {mass of solute}}{\text {Volume of solute}}

1.0g/ml=\frac{116g}{\text {Volume of solute(water)}}

{\text {Volume of solute(water)}}=116ml

Thus the volume of water to be added is 116 ml.

6 0
3 years ago
In another experiment, the student titrated 50.0mL of 0.100MHC2H3O2 with 0.100MNaOH(aq) . Calculate the pH of the solution at th
Helen [10]

pH=8.87

<h3>Further explanation</h3>

Reaction

C₂H₄O₂+NaOH⇒CH₃COONa+H₂O

at the equivalence point = mol C₂H₄O₂= mol NaOH

mol C₂H₄O₂ : 50 x 0.1 = 0.5 mlmol=5.10⁻⁴ mol

The two reactants have completely reacted, and there is only salt(CH₃COONa) and water(H₂O), there will be hydrolysis

For acids from weak acids and strong bases (the solution is alkaline) then the calculation:

\tt [OH^-]=\sqrt{\dfrac{Kw}{Ka}\times M }

M=anion concentration=CH₃COO⁻

Ka=acid constant(for CH₃COOH,Ka=1.8.10⁻⁵)

\tt [OH^-]=\sqrt{\dfrac{10^{-14}}{1.8.10^{-5}}\times 0.1 }

\tt [OH^-]=\sqrt{5.6.10^{-11}}=7.483\times 10^{-6}

pOH=6-log 7.483=5.13

pH= 14 - 5.13=8.87

5 0
3 years ago
Given the balanced reaction: Zn + 2HCl H2 + ZnCl2 How many grams of zinc are needed to produce 5 grams of H2?
kumpel [21]

Answer:

161.9gZn

Explanation:

Hello there!

In this case, according the given balanced chemical reaction:

Zn + 2HCl\rightarrow  H_2 + ZnCl_2

It is possible to evidence the 1:1 mole ratio of hydrogen (molar mass = 2.02 g/mol) to zinc (atomic mass = 65.41 g/mol) which is used to calculate the grams of the latter needed for the production of 5 grams of the former via stoichiometry:

5gH_2*\frac{1molH_2}{2.02gH_2}*\frac{1molZn}{1molH_2} *\frac{65.41gZn}{1molZn}\\\\=161.9gZn

Best regards!

5 0
3 years ago
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