<em>the </em><em>new </em><em>volume </em><em>will </em><em>be </em><em>8</em><em>2</em><em>×</em><em>1</em><em>0</em><em>-</em><em>3</em><em> </em><em>L </em><em>or </em><em>0</em><em>.</em><em>0</em><em>0</em><em>8</em><em>2</em><em> </em><em>L</em>
Equation: 2H₂ + O₂ → 2H₂O
Now, Given mass of Oxygen = 192 g
Molar mass of Oxygen = 16 g/mol
No. of moles in Oxygen = 16/192 = 0.0833
Now, for every mole of Oxygen, 2 mole of Hydrogen will form,
so, Number of moles of Hydrogen = 0.0833 * 2 = 0.167
Given mass = Number of Moles * Molar mass
Given mass = 0.167 * 2
m = 0.33 g
In short, Your Answer would be: 0.33 g
Hope this helps!
Answer: Volume of water to be added is 116 ml.
Explanation:
Elevation in boiling point is given by:

= elevation in boiling point
i= vant hoff factor = 1 (for non electrolyte)
=boiling point constant = 
m= molality

Density of solvent =

(1kg=1000g)
Mass of solute (water) = x g


Density of solute =


Thus the volume of water to be added is 116 ml.
pH=8.87
<h3>
Further explanation</h3>
Reaction
C₂H₄O₂+NaOH⇒CH₃COONa+H₂O
at the equivalence point = mol C₂H₄O₂= mol NaOH
mol C₂H₄O₂ : 50 x 0.1 = 0.5 mlmol=5.10⁻⁴ mol
The two reactants have completely reacted, and there is only salt(CH₃COONa) and water(H₂O), there will be hydrolysis
For acids from weak acids and strong bases (the solution is alkaline) then the calculation:
![\tt [OH^-]=\sqrt{\dfrac{Kw}{Ka}\times M }](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D%5Csqrt%7B%5Cdfrac%7BKw%7D%7BKa%7D%5Ctimes%20M%20%7D)
M=anion concentration=CH₃COO⁻
Ka=acid constant(for CH₃COOH,Ka=1.8.10⁻⁵)
![\tt [OH^-]=\sqrt{\dfrac{10^{-14}}{1.8.10^{-5}}\times 0.1 }](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D%5Csqrt%7B%5Cdfrac%7B10%5E%7B-14%7D%7D%7B1.8.10%5E%7B-5%7D%7D%5Ctimes%200.1%20%7D)
![\tt [OH^-]=\sqrt{5.6.10^{-11}}=7.483\times 10^{-6}](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D%5Csqrt%7B5.6.10%5E%7B-11%7D%7D%3D7.483%5Ctimes%2010%5E%7B-6%7D)
pOH=6-log 7.483=5.13
pH= 14 - 5.13=8.87
Answer:

Explanation:
Hello there!
In this case, according the given balanced chemical reaction:

It is possible to evidence the 1:1 mole ratio of hydrogen (molar mass = 2.02 g/mol) to zinc (atomic mass = 65.41 g/mol) which is used to calculate the grams of the latter needed for the production of 5 grams of the former via stoichiometry:

Best regards!