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padilas [110]
3 years ago
14

According to the Arrhenius concept, which of the following substances is NOT a base in aqueous solutionsA. NH3B. LiOHC. NaOHD. H

2OE. Ca(OH)2
Chemistry
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

NH₃ (Option A)

Explanation:

Arrhenius theory explained that the acids are the ones that have H⁺, either H in its formula. Following this, the bases are the ones that have OH⁻ , either OH and its formula.

It can be used only with compounds with H, or OH.

So the ammonia is not a base, as Arrhenius theory.

It is known that ammonia behaves as a weak base, but it does not have hydroxide ions that can yield to water

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4. How many atoms are in 32.6 g of Oxygen?
Natali5045456 [20]

Hey there!

Oxygen has a molar mass of 16. That means 16g of oxygen is 1 mole.

32.6 ÷ 16 = 2.0375 moles

We have 2.0375 moles.

There are 6.022 x 10²³ atoms in one mole.

2.0375 x 6.022 x 10²³

1.3 x 10²⁴

There are 1.3 x 10²⁴ atoms in 32.6 grams of oxygen.

Hope this helps!

7 0
3 years ago
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Solid substance A has a melting point of 100°C. Liquid substance B has a freezing point of 110°C. For each substance, identify i
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Answer:

both will be at liquid state. the particles will move rapidly in all directions and will collide with other particles in random motion

4 0
3 years ago
What name should be used for the ionic compound LiI?
timurjin [86]

What name should be used for the ionic compound LiI?

The name that should be used for the ionic compound LiI is Lithium iodide. When naming ionic compounds, you have to take into consideration pairing of two components. 

5 0
3 years ago
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Use the diagram to determine: How many atoms are on the Right side =___ How many atoms are on the Left side = ____ Is this a Bal
Lady_Fox [76]

Answer:

on the right side two and on left side it is6 yes it is a balanced equation pls mark me as the brainliset hope it helps you

5 0
3 years ago
a rectangular piece of aluminum foil measures 13.72 cm x 8.63 cm and has a mass of 3.1 g. Find how thick it is
Leona [35]

The two dimensions of aluminum foil are given 13.72 cm and 8.63 cm respectively with mass  3.1 g.

The density of aluminum is 2.7 g/cm^{3}. It is defined as mass per unit volume thus, volume of aluminum can be calculated as follows:

V=\frac{m}{d}

Putting the values.

V=\frac{3.1 g}{2.7 g/cm^{3}}=1.148 cm^{3}

The volume of cuboid is l\times b\times h, the length and breadth are given, height can be calculated as follows;

h=\frac{V}{l\times b}

Putting the values,

h=\frac{1.148 cm^{3}}{(13.72 cm)(8.63 cm)}=0.009695 cm

Or, approximately 9.7\times 10^{-3}cm

Therefore, thickness of aluminum foil is 9.7\times 10^{-3}cm

7 0
3 years ago
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