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Ilya [14]
2 years ago
10

Which of the following you is true for a limiting reactant

Chemistry
1 answer:
skad [1K]2 years ago
3 0

Answer:

  • <em><u>C) The limiting reactant has the lowest ratio of moles available / coefficient in the balanced equation.</u></em>

Explanation:

Please, find attached a complete question to determine which of the statements is or are true for a limiting reactant in a chemical equation.

First, remember that the limiting reactant is the substance that is consumed completely while the excess reactant is the substance that does not react completely.

The limiting reactant is found comparing the stoichiometry ratio and the actual ratio between the reactants.

The stoichiometry ratio is found using the coefficientes of the chemical equation.

For illustration, assume the general chemical equation:

         aA+bB\rightarrow cC+dD

The stoichiometric ratio of the reactants is:

          a\text{ }moles\text{ }of\text{ }A/b\text{ }moles\text{ }of\text{ }B

If the ratio of the available moles of substance A to the available moles of  substance B is greater than the stoichiometric ratio, it means that there are more moles of the substance A than what is needed to react with the available moles of substance B, then A will be in excess and B will B the limiting reactant.

If, on the contrary, the ratio of the available moles of substance A to the available moles of  substance B is is less than the stoichiometric ratio, then substance A is less than the necessary to make the all the moles of substance B react, meaning that the substance A will limit the reaction (it will be consumed completely), while the substance B will be in excess.

As for the options:

<em><u>A) The limiting reactant is has the lowest coefficient in a balanced equation.</u></em>

This is false, since it is not the magnitude of the coefficiente what determines the limiting reactant, but the comparison of the ratios.

<u><em>B) The limiting reactant is the reactant for which you have the fewest number of moles.</em></u>

This is false because it is not the number of moles what determines the limiting reactant , but the comparison of the ratios.

<u><em>C) The limiting reactant has the lowest ratio of moles available / coefficient in the balanced equation.</em></u>

This is true as proved below.

The stoichiometric ratio of the reactants is:

          a\text{ }moles\text{ }of\text{ }A/b\text{ }moles\text{ }of\text{ }B

The actual ratio is:

         available\text{ }moles\text{ }of\text{ }A/available\text{ }moles\text{ }of\text{ }B

Assume the first ratio is less than the second (which describes when the substance A is in excess and the limiting reactant is the substance B).

a\text{ }moles\text{ }of\text{ }A/b\text{ }moles\text{ }of\text{ }B

Change the relation to show the ratios of moles available of each substance to the cofficient in the chemical equation:

available\text{ }moles\text{ }of\text{ }B/b\text{ }moles\text{ }of\text{ }B

Then, in the scenary that the limiting reactant is the substance B, the ratio of the left is lower than the ratio of the right, which is the same that limiting reactant has the lowest ratio of moles available / coefficient in the balanced equation.

<em><u>D) The limiting reactant has the lowest ratio of coefficients in the balanced eqution/moles available.</u></em>

<em><u /></em>

This ratio is the inverse of the ratio of the previous statement, thus the relation is inverse, and, since the previous statement was true, this statement is false.

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Answer:

<h2>D</h2>

Explanation:

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Answer:

Oxidation by FAD  

Explanation:

1. Oxidation by NAD⁺

Succinate ⇌ Fumarate + <u>2H⁺ + 2e⁻</u>;                  E°´ =  -0.031 V  

<u>NAD⁺ + </u><u>2H⁺ + 2e⁻</u><u> ⇌ NADH + H⁺;                    </u>  E°´ = <u> -0.320 V</u>

Succinate + NAD⁺ ⇌ Fumarate  + NADH + H⁺; E°' =  -0.351 V

2. Oxidation by FAD

Succinate ⇌ Fumarate + 2H⁺ + 2e⁻;        E°´ = -0.031 V  

<u>FAD + 2H⁺ + 2e⁻ ⇌ FADH₂;                   </u>  E°´  = <u>-0.219 V </u>

Succinate + FADH₂ ⇌ Fumarate + FAD; E°' = -0.250 V

Neither reaction is energetically favourable, but FAD has a more positive half-cell potential.

FAD is the stronger oxidizing agent.

The oxidation by FAD has a more positive cell potential, so it is more favourable energetically.  

 

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Answer:

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Explanation:

im not totaly sure

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A catalyst of copper mixed with zinc oxide and alumina is used in industry for this production of methanol. Explain the function
arsen [322]

Answer:Copper oxide + Hydrogen → Copper + Water

Copper sulfate + Zinc → Zinc sulfate + copper

Aluminium + Copper chloride → Aluminium chloride + copper

Copper + Oxygen → Copper oxide

Explanation:

Chemical reactions involves chemical combination of compounds or elements as reactants to form other compounds or elements.

In this case, various reactants given will react exhibiting different types of chemical reactions to form products.

First reaction

Aluminium + Copper chloride → Aluminium chloride + Copper

This is a single displacement reaction in which aluminium which is a more reactive element than copper displaces copper from its salt.

Second reaction

Copper oxide + Hydrogen → Copper + water

It is another example of a single replacement reaction. Hydrogen displaces less reactive metals from their oxide to form water and the metal.

Third reaction

Copper sulfate + Zinc → Zinc sulfate + copper

It is another single replacement reaction.

Zinc is more reactive than copper and therefore replaces copper from its salt solution.

Fourth reaction

Copper + Oxygen → Copper oxide

It is a synthesis reaction.

A synthesis reaction is a reaction in which elements or small compounds combine to form single compound.

4 0
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