(a) The frequency of the motion after the collision is 0.71 Hz.
(b) The maximum angular displacement of the motion after the collision is 16.3⁰.
<h3>Speed of the 2.2 kg ball when it collides with 2.7 kg ball</h3>
The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 0.1)
v = 1.4 m/s
<h3>Final speed of both balls after collision</h3>
The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.
Pi = Pf
m₁v₁ + m₂v₂ = vf(m₁ + m₂)
2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)
3.08 = 4.9vf
vf = 3.08/4.9
vf = 0.63 m/s
<h3>Maximum displacement of the balls after the collision</h3>
P.E = K.E

<h3>Maximum angular displacement</h3>
The maximum angular displacement of the balls after the collision is calculated as follows;

<h3>Frequency of the motion</h3>

Learn more about maximum angular displacement here: brainly.com/question/13665036
She needs to lose an average of 10 pounds per week in order to fulfill her expectation. Go Becky !
Esophagus.
The esophagus is a long straight tube about 10 inches long that arises from the pharynx, passes through the diaphragm and continues into the stomach. The muscular walls of the esophagus move food into the stomach by peristalsis.
Answer:
v = 2.348 m/s
Explanation:
Let:
h be the height of the child above the swing's low point,
v be the speed at the low point.
When the ropes make angle 3
25 deg. with the vertical:
h = 3.00(1 - cos(25)).
Equating potential energy at the high point to kinetic energy at the low point:
29.0 * 9.81 * 3.00(1 - cos(25)) = 29.0v^2 / 2
79.96 =29.0v^2 / 2
v = 2.348 m/s
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