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pochemuha
3 years ago
5

The law of inertia applies to

Physics
2 answers:
navik [9.2K]3 years ago
6 0
C) both moving and non-moving objects
As, it is same as the Newton's  first law motion
EleoNora [17]3 years ago
6 0
I believe the answer is C. both moving and nonmoving objects.
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A small boat sailed straight north out of a harbor in strong east wind (blowing from west to east). After sailing for 120 minute
Amiraneli [1.4K]

it can be said that  the speed of the east wind is

v=0.3608m/s

From the question we are told

A small boat sailed <u>straight </u>north out of a harbor in <em>strong </em>east wind (blowing from west to east).

After sailing for 120 minutes, it ended up hitting a buoy 60^\circ60 ∘ to the north-east of the harbor. If the straight-line distance between the buoy and the harbor is 3 km,

  • what is the speed of the east wind?.

<h3> the speed of the east wind</h3>

Generally the equation for the distance  is mathematically given as

BA=3000sin60

BA=2598.07m

Therefore

the speed of the east wind

V_w=\frac{BA}{120*60}\\\\V_w=\frac{2598.07}{120*60}

v=0.3608

For more information on this visit

brainly.com/question/22568180

7 0
2 years ago
Which wind blows 30 latitude in both hemisphere almost to the equator
andriy [413]
Trade winds
Hope it help
7 0
3 years ago
•What is the gravitational potential energy of a girl
disa [49]

Answer:

1960 joule

Explanation:

8 0
3 years ago
Qualitative studies draw conclusions.<br> True<br> False
Marina86 [1]

Answer:

Hey there!

This is false. A qualitative study is about how a thing looks, not based on any mathematical or scientific data. Quantitative studies, on the other hand, draw conclusions.

Let me know if this helps :)

3 0
3 years ago
The top and bottom surfaces of a metal block each have an area of A = 0.030 m 2, and the height of the block is d = 0.11 m. At t
Marat540 [252]

Answer:

Shear modulus is equal to 9.82\times 10^{10}N/m^2

Explanation:

We have given area A=0.030m^2

Force is given F_1=F_2=30\times 10^6N

Height of the block d = 0.11 m

Change in height of the block \Delta d=1.12\times 10^{-3}m

Stress is given by

stress=\frac{force}{area}

stress=\frac{30\times 10^6}{0.030}=10^9N/m^2

Strain is equal to

strain=\frac{\Delta d}{d}

strain=\frac{1.12\times 10^{-3}}{0.11}=10.18\times 10^{-3}

Shear modulus is equal to

Shear modulus =\frac{stress}{strain}

=\frac{10^9}{10.18\times 10^{-3}}=9.82\times 10^{10}N/m^2

6 0
3 years ago
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