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Stolb23 [73]
2 years ago
14

A small block with a mass of 0.120 kg is attached to a cord passing through a hole in a frictionless, horizontal surface (Fig. 6

.34). The block is originally revolving at a distance of 0.40 m from the hole with a speed of 0.70 m/s. The cord is then pulled from below, shortening the radius of the circle in which the block revolves to 0.10 m. At this new distance, the speed of the block is observed to be 2.80 m/s.
(a) What is the tension in the cord in the original situation when the block has speed v = 0.70 m/s? (b) What is the tension in the cord in the final situation when the block has speed v = 2.80 m/s? (c) How much work was done by the person who pulled on the cord?
Physics
1 answer:
Rina8888 [55]2 years ago
7 0

Answer:

a) 0.147 N

b) 9.408 N

c) 9.261 N

Explanation:

The tension on the cord is the only force keeping the block in circular motion, thus representing the entirety of its centripetal force \frac{mv^{2} }{r}. Plugging in values for initial and final states and we get answers for a and b. The work done by the person causes the centripetal force to increase, and thus is the difference between the final tension and the initial tension.

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Work = (force) x (distance)

When a force of 150 N pushes through a distance of 13 meters,
it does

             Work = (150 N) x (13 m) = 1,950 joules .
6 0
3 years ago
Which of these cultures did NOT make major contributions to astronomy?
Svetlanka [38]
I can't particularly place what Icelandic contributed.

But every  other culture contributed majorly.

So I would go for option b.
6 0
3 years ago
17. Suppose you were standing on a scale in an elevator in free fall. What would the scale read?
lianna [129]

17

What would the scale read? zero

18 In free fall you are being pulled by a gravity. "Truly" weightless presumably happens in deep space where there is nothing to pull you.

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Roller coasters are for fun seekers. NASA is for science

5 0
3 years ago
Read 2 more answers
A spherically-spreading EM wave comes from a 104.0 W source. At a distance of 9.6 m, what is the intensity of the wave?
Nookie1986 [14]

Answer:

Approximately 0.0898 W/m².

Explanation:

The intensity of light measures the power that the light delivers per unit area.

The source in this question delivers a constant power of \rm 104.0\; W. If the source here is a point source, that \rm 104.0\; W of power will be spread out evenly over a spherical surface that is centered at the point source. In this case, the radius of the surface will be 9.6 meters.

The surface area of a sphere of radius r is equal to 4\pi r^{2}. For the imaginary 9.6-meter sphere here, the surface area will be:

\rm 4\pi \times (9.6\; m)^{2} \approx 1158.12\; m^{2}.

That \rm 104.0\; W power is spread out evenly over this 9.6-meter sphere. The power delivered per unit area will be:

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8 0
3 years ago
How do noise canceling headphones work?
postnew [5]

Answer:

B.) by interfering with sound waves

Explanation:

As we know that the interference of sound waves is of two types

1). constructive interference

2). destructive interference

now we know that constructive interference means the resultant intensity will be more than the intensity of interfering waves as here two waves are in same phase.

In destructive interference the resultant of two waves is given by the minimum resultant of the intensity as here the phase of two waves are opposite to each other.

So we will say that

I = \sqrt{(I_1 + I_2 + 2\sqrt{I_1I_2}cos\theta)}

here in case of noise cancelling headphones we know that the phase of noise is always made in opposite phase with the sound which is used to cancelled the noise.

This will reduce the noise and we will get a clear sound

5 0
3 years ago
Read 2 more answers
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