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Ierofanga [76]
2 years ago
13

What is the worlds most common acid and also the worlds most commin base

Physics
1 answer:
mrs_skeptik [129]2 years ago
3 0

Answer: Water is the world's most common acid and base.

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Q|C The speed of a one-dimensional compressional wave traveling along a thin copper rod is 3.56 km/s . The rod is given a sharp
Gekata [30.6K]

The length of rod in terms v(r) and t is L = [  Δt / (1/343) - (1/v(r)) ].

3.56 km/s is the speed of a one-dimensional compressional wave moving along a thin copper rod.

At one end of the rod, a hard hammer strike is delivered. With a time interval of Δt between the two pulses, a listener at the other end of the rod hears the sound twice as it travels through the metal and the air.

The time interval is given by t = L/v.

The delay between pulses arrivals is:

Δt = L [(1/v(air)) - (1/v(copper))]

Now,

When the copper rod is swapped out for a different substance and the sound speed is measured as v(r).

The speed of air, v(air) = 343 m/s

Then,

L = [  Δt / (1/v(air)) - (1/v(r)) ]

L = [  Δt / (1/343) - (1/v(r)) ]

Here L is the length of the rod, Δt is in seconds and v(r) is the speed of sound in the rod.

Learn more about speed here:

brainly.com/question/13943409

#SPJ4

8 0
1 year ago
When two oceanic plates collide, it creates _____.
jonny [76]

At the subduction zone a very deep trench is formed in the ocean floor. Oceanic and oceanic plate convergence result in the formation of volcano chains. The crust that is pulled under or subducted melts to form magma. This magma rises to the top of the overriding oceanic plates and erupts on the ocean floor.
So the answer would be Volcano
5 0
3 years ago
Read 2 more answers
Interactive Solution 9.1 presents a model for solving this problem. The wheel of a car has a radius of 0.380 m. The engine of th
Vilka [71]

Answer:

The magnitude of the static frictional force is 1200 N

Explanation:

given information :

radius, r = 0.380 m

applied-torque, τ1 = 456 N

The car has a constant velocity, thus the acceleration is zero

α = 0

Στ = I α

τ1 - τ2 = I α

τ2 = counter-torque

τ1 - τ2 = 0

τ1 = τ2

r x F_{s} = τ1

F_{s} = the static frictional force (N)

F_{s} = τ1 /r

  = 456 N/0.380 m

  = 1200 N

7 0
3 years ago
A 1700kg rhino charges at a speed of 50.0km/h. what average force is needed to bring the rhino to a stop in 0.50s?
uranmaximum [27]
From 50km/h to 0km/h in 0.5s we need next acceleration:
First we convert km/h in m/s:
50km/h = 50*1000/3600=13.8888 m/s
a = v/t = 13.88888/0.5 = 27.77777 m/s^2

Now we use Newton's law:

F=m*a

F=1700*27.7777 = 47222N
6 0
3 years ago
HELP=BRAILIEST+40 POINTS PLS HELP MEEEEEEEEEE
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B: gravity is absent in space
8 0
3 years ago
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