Explanation:
you made an error while putting the unit of velocity
acceleration = change in vel in time
a = (∆v/t)
the initial vel (u) =0m/s
the final vel (v) = 5,500m/s
time (t) = 8min + 30sec = 480 + 30
510s
a = (5,500 - 0)/510
5,500/510
a = 10.78m/s²
Answer:
a) the result capacitor
ct=c1+c2+c3+c4
ct=2×10^-6+4×10^-6+6×10^-6+8×10^-6
ct=20×10^-14
b)q=ct×v
q=20×10^-14×50
q=1000×10^-14 c
Explanation:
c)v1=q/ct
v1=1000×10^-14/20×10^-14
v1=50 volt
v2=
Answer:
334.314 (kJ)
Explanation:
1) the formula for the required energy is: Q=c*m(Bp-t), where c - 4100 J/kg*C; m - 0.9 kg; Bp - 100.6 C; t - 10 C.
2) according to the formula above:
Q=4100*0.9*(100.6-10)=41*9*906=334314 (J).
1 AU ~150,000,000 km/160 km/h, which gives you hours.
24 hours in a day...
365 days in a year...
If you are planning on a return trip plan on your 5 to 6x great grandchildren picking you up at the space port.
Answer:
12.7m/s
Explanation:
Given parameters:
Mass of the diver = 77kg
Height = 8.18m
Unknown:
Speed of the diver before hitting the water = ?
Solution:
The speed of the diver before hitting the water is the final velocity.
To solve this problem, we use the expression below;
v² = u² + 2gH
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
H is the height
Now insert the parameters and solve;
v² = 0² + 2 x 9.8 x 8.18
v² = 160.328
v = 12.7m/s