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Morgarella [4.7K]
2 years ago
14

Find the number c that satisfies the conclusion of the Mean Value Theorem. f(x) = x/(x + 4)

Mathematics
1 answer:
Olin [163]2 years ago
7 0

Answer:

x^4

Step-by-step explanation:

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Compare √7 and √12 plotted on the number line. What is the approximate difference in tenths between the two values? A number lin
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Consider this three-digit sequence: 943. Is the first digit the largest or the second digit the smallest, AND, is the third digi
Delicious77 [7]
<span>your question isn't very clear, but I'll try to answer

</span><span>943
</span>the first digit (9) is the largest, the second digit (4) is the 2nd largest, and the third digit (3) is the smallest.
the first digit is odd, the second is even, and the third is odd
8 0
3 years ago
Solve 16x+9=9y−2x16x+9=9y−2x for y
denis23 [38]
16x + 9 = 9y-2x   Add 2x to both sides
18x + 9 = 9y        Divide both sides by 9
  2x + 1 = y           Switch the sides to make it easier to read
         y = 2x + 1
 
6 0
3 years ago
A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult
klio [65]

Answer:

<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>

Step-by-step explanation:

Probability = \frac{Required outcomes}{Total possible outcomes}

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

<em>Total possible outcomes: 20</em>


<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = \frac{n(Odd)}{Total} = \frac{10}{20} = \frac{1}{2} = 0.5


Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = \frac{n(5)}{Total} = \frac{4}{20} = \frac{1}{5} = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = \frac{2}{20}=\frac{1}{10}=0.1

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6

7 0
3 years ago
Please help me with this question
ddd [48]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve ~

Total Mini - Easter eggs = 1345

Number of students = 26

So, let's find how many eggs will each student get through division ~

\qquad \tt  \dashrightarrow \: \dfrac{1345}{26}  = 51 +remainder= 19

So, each student will get 51 mini - Easter egg each.

And there would be 19 remaining eggs in there ~

4 0
2 years ago
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