Answer:
18 grams of water, will be produced from 4 g of H₂ and 16g of O₂
Explanation:
Reaction: 2H₂ + O₂ ⇒ 2H₂O
Moles = Mass / Molar mass
Molar mass H₂ = 2g/m
Molar mass O₂ = 32 g/m
4g /2g/m = 2moles
16g / 32 g/m = 0.5 moles
Ratio is 2:1
For 2 moles of hydrogen, I need 1 mol of oxygen; I have 2 moles of H₂, but I only have 0.5 of O₂, so the O₂ is the limiting reagent.
1 mol of O₂ produces 2 mol of water
0.5 moles of O₂ will produce, the double → 1 mol of water.
Molar mass of water is 18 g/m
1 mol . 18 g/m = 18 g
Uhhhhhhhhhh................
Answer:
0.9612 g
Explanation:
First we <u>calculate how many moles are there in 3.00 g of CCl₃F</u>, using its <em>molar mass</em>:
- 3.00 g CCl₃F ÷ 137.37 g/mol = 0.0218 mol CCl₃F
Now, we need to calculate how many grams of N₂O would have that same number of molecules, or in other words, <em>the same amount of moles</em>.
Thus we <u>calculate how many grams would 0.0218 moles of N₂O weigh</u>, using the <em>molar mass of N₂O</em> :
- 0.0218 mol N₂O * 44.013 g/mol = 0.9612 g N₂O
Susan should follow PEMDAS,
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction,
So, the first step should be, to solve the equation in the parentheses.
I hope this helps!