Surface area of the cylinder = 816.4 sq. ft.
Solution:
Height of the cylinder = 21 ft
Diameter of the cylinder = 10 ft
Radius of the cylinder = 10 ÷ 2 = 5 ft
Use the value of
= 3.14
Surface area of the cylinder = ![2 \pi r h+2 \pi r^{2}](https://tex.z-dn.net/?f=2%20%5Cpi%20r%20h%2B2%20%5Cpi%20r%5E%7B2%7D)
Substitute the given values in the surface area formula, we get
Surface area of the cylinder ![$=2\times3.14\times 5\times 21+2 \times3.14\times 5^2](https://tex.z-dn.net/?f=%24%3D2%5Ctimes3.14%5Ctimes%205%5Ctimes%2021%2B2%20%5Ctimes3.14%5Ctimes%205%5E2)
![=659.4+157](https://tex.z-dn.net/?f=%3D659.4%2B157)
ft²
Hence the surface area of the cylinder is 816.4 sq. ft.