Answer:
X = 2146.05 m
Explanation:
We need to understand first what is the value we need to calculate here. In this case, we want to know how far from the starting point the package should be released. This is the distance.
We also know that the plane is flying a certain height with an specific speed. And the distance we need to calculate is the distance in X with the following expression:
X = Vt (1)
However we do not know the time that this distance is covered. This time can be determined because we know the height of the plain. This time is referred to the time of flight. And the time of flight can be calculated with the following expression:
t = √2h/g (2)
Where g is gravity acceleration which is 9.8 m/s². Replacing the data into the expression we have:
t = √(2*2500)/9.8
t = 22.59 s
Now replacing into (1) we have:
X = 95 * 22.59
<h2>
X = 2146.05 m</h2>
This is the distance where the package should be released.
Hope this helps
Answer:
The image distance from right lens is 2.86 cm and image is real.
Explanation:
Given that,
Focal length of left lens = 10 cm
Focal length of right lens = 5 cm
Distance between the lenses d= 15 cm
Object distance = 50 cm
We need to calculate the image distance from left lens
Using formula of lens
Put the value into the formula
We need to calculate the image distance from right lens
The object distance will be
Using formula of lens
Put the value into the formula
The image is real.
Hence, The image distance from right lens is 2.86 cm and image is real.
Answer:
mesuring heigh and weight is important
W, because as time is moving up at a consistent rate the speed is as well, creating the straight line.
