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White raven [17]
3 years ago
7

A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Check all that

apply. a.The period is independent of the length of the wire. b.The period is inversely proportional to the length of the wire. c.The period is proportional to the suspended mass. d.The period is inversely proportional to the suspended mass. e.The period is proportional to the length of the wire. f.The period is independent of the suspended mass.
Physics
1 answer:
9966 [12]3 years ago
3 0

Answer:

f.The period is independent of the suspended mass.

Explanation:

The period of a pendulum is given by

T=2 \pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration due to gravity

From the formula, we see that:

1) the period of the pendulum depends only on its length, L, and it is proportional to the square root of the length

2) the period does not depend neither on the mass of the pendulum, nor on its amplitude of oscillation

So, the only correct statements are

f.The period is independent of the suspended mass.

Note: statement "e.The period is proportional to the length of the wire" is also wrong, because the period is NOT proportional to the length of the wire, but it is proportional to the square root of it.

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Complete Question

The  complete question is shown on the first  uploaded image

Answer:

The  value  is  J_n  =  -0.864 \  A/cm^2

Explanation:

Generally for an n-type semiconductor the current density is mathematically represented  as

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Here  p_{n_o} is mathematically represented as

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=>      p_{n_o}  = \frac{(1.5*10^{10})^2}{10^{16}}

=>      p_{n_o}  = 2.25 *10^{4} \  cm^{-3}

So

    d p_{n_o} =  P_n0 - p_{n_o}

From the diagram  P_n0  =  10^8 * p_{n_o}

=>  P_n0  =  10^8 * (2.25 *10^{4} )

So

   d p_{n_o} =  10^8 * (2.25 *10^{4} ) - 2.25 *10^{4}

      d p_{n_o} =  2.25 *10^{12} cm^{-3}

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substitute

    1.60 *10^{-19} \  C for  q  and  w_2 =50 nm =  50*10^{-9} m  =  5*10^{-6} cm

and from the diagram  w_1 =0 \ cm

So

    J_n  =  -1.60 *10^{-19} *12 *  \frac{2.25 *10^{12} }{ 5*10^{-6} - 0 }

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6 0
3 years ago
Dimension of radius of sphere​
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Answer:

The dimension is L

Explanation:

Dimension analysis is a method of representing quantities majorly with respect to some fundamental quantities of mass (M), length (L), time (T).

A sphere has a definite volume which relates to its radius by:

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In this equation \pi is a dimensionless quantity, and the unit of v is m^{3}.

But, metre is a measure of length, thus it has a dimension of L.

So that,

m^{3} ≅ L^{3}

Then,

L^{3} = r^{3}

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Answer:

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Explanation:

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