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White raven [17]
3 years ago
7

A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Check all that

apply. a.The period is independent of the length of the wire. b.The period is inversely proportional to the length of the wire. c.The period is proportional to the suspended mass. d.The period is inversely proportional to the suspended mass. e.The period is proportional to the length of the wire. f.The period is independent of the suspended mass.
Physics
1 answer:
9966 [12]3 years ago
3 0

Answer:

f.The period is independent of the suspended mass.

Explanation:

The period of a pendulum is given by

T=2 \pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration due to gravity

From the formula, we see that:

1) the period of the pendulum depends only on its length, L, and it is proportional to the square root of the length

2) the period does not depend neither on the mass of the pendulum, nor on its amplitude of oscillation

So, the only correct statements are

f.The period is independent of the suspended mass.

Note: statement "e.The period is proportional to the length of the wire" is also wrong, because the period is NOT proportional to the length of the wire, but it is proportional to the square root of it.

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When Magenta light is shown on a green surface, it looks black.

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Answer:

The resultant velocity is <u>169.71 km/h at angle of 45° measured clockwise with the x-axis</u> or the east-west line.

Explanation:

Considering west direction along negative x-axis and north direction along  positive y-axis

Given:

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Now, considering the given directions, the velocities are given as:

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Velocity in north direction is, \overrightarrow{v_2}=120\ \vec{j}

Now, since v_1\ and\ v_2 are perpendicular to each other, their resultant magnitude is given as:

|\overrightarrow{v_{res}}|=\sqrt{|\overrightarrow{v_1}|^2+|\overrightarrow{v_2}|^2}

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|\overrightarrow{v_{res}}|=\sqrt{(120)^2+(120)^2}\\\\|\overrightarrow{v_{res}}|=120\sqrt{2} = 169.71\ km/h

Let the angle made by the resultant be 'x' degree with the east-west line or the x-axis.

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x=\tan^{-1}(\frac{|v_2|}{|v_1|})\\\\x=\tan^{-1}(\frac{120}{-120})=\tan^{-1}(-1)=-45\ deg(clockwise\ angle\ with\ the\ x-axis)

Therefore, the resultant velocity is 169.71 km/h at angle of 45° measured clockwise with the x-axis or the east-west line.

4 0
3 years ago
This is a measure of the quantity of matter.
emmainna [20.7K]

The measure of the quantity of matter would be mass. Mass is measured in kilograms. I hope this helped!:)

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Answer:

c. The steady-state value of the current depends on the resistance of the resistor.

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