Density=mass/volume
mass= 5kg
volume: πr²h
= π(2)²(5)
=62.83 cm³ or 0.06283 m³
density: m/v
d= 5/0.06283 m³
d=79.57 kg/m³
Hope I helped :)
An Ohm or a electrical resistance is a measure of the amount of electrical energy transferred by an electric charge as it moves from one point to another circuit. The voltage between two points in a circuit can be measured with a voltmeter.
The kinetic energy of the proton is 1982.31 MeV.
We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by
Eo = m₀ . c²
where Eo is rest energy, m₀ is rest mass and c is the speed of light (3 x 10⁸ m/s).
The total energy of object can be described as
E = Eo / √(1 - v²/c²)
where E is total energy, v is the object speed.
Kinetic energy can be defined as energy change from rest energy until total energy. It can be determined as
KE = E - Eo
where KE is kinetic energy.
From the question above, we know that :
m₀ = 1.6 x 10¯²⁷ kg
c = 3 x 10⁸ m/s
v = 0.95c
Find the rest energy
Eo = m₀ . c²
Eo = 1.6 x 10¯²⁷ . (3 x 10⁸)²
Eo = 1.44 x 10¯¹⁰ joule
Eo = 1.44 x 10¯¹⁰ / (1.6 x 10¯¹⁹) eV
Eo = 900 x 10⁶ eV
Eo = 900 MeV
Determine the total energy
E = Eo / √(1 - v²/c²)
E = 900 / √(1 - (0.95c)²/c²)
E = 900 / 0.31
E = 2882.31 MeV
Calculate the kinetic energy
KE = E - Eo
KE = 2882.31 MeV - 900 MeV
KE = 1982.31 MeV
Find more on relativistic energy at: brainly.com/question/23920189
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when we throw an arrow , we first stretch the string of the bow. while stretching the string of the bow, the work done by us in stretching the bowstring gets stored as potential energy in the bow. This potential energy of the bow is transformed into kinetic energy when the bowstring is released and this gives the momentum and Kinetic energy to the arrow.
For more details for transfer of energy visit the given site link :-
https://brainly.in/question/22705654