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4 years ago

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Physics

1 answer:

guajiro [1.7K]4 years ago

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A flea jumps straight up to a maximum height of 0.490 m . What is its initial velocity v0 as it leaves the ground?

zzz [600]

Answer:

$\huge\boxed{\sf v_o=3.1\ m/s}$

Explanation:

Given Data:

Acceleration due to gravity = g = -9.8 m/s²

Maximum Height = h = 0.490 m

At h, $v_f$ = 0

Required:

$v_o=?$

Formula:

$2gh=v_f^2-v_o^2$

Solution:

Put the givens

$2 (-9.8) (0.490) = (0)\² - v_o^2\\\\-9.604=-v_o^2\\\\9.604=v_o^2\\\\Take \ sqrt\ on \ both \ sides\\\\\sqrt{9.604}=v_o^2\\\\3.1 \ m/s=v_o\\\\v_o=3.1\ m/s\\\\\rule[225]{225}{2}$

3 0

2 years ago

All of the waves in the electromagnetic spectrum are _______ waves.

crimeas [40]

All of the waves in the electromagnetic spectrum are transverse waves.

5 0

3 years ago

Read 2 more answers

A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance x from the 50

Rom4ik [11]

Answer:

x=0.01457 m

Explanation:

From parallel axis theorem

I=Icm+mh²

where h=x

The rotational inertia about its center of mass is

Icm=mL²/12

where L=1.0 m

Thus T=4.8s we obtain

$T=2\pi \sqrt{\frac{mL^{2}/12+mx^{2} }{mgx} }\\ T=2\pi \sqrt{\frac{L^{2} }{12gx}+x/g }\\ T^{2}=4\pi^{2}(\frac{L^{2} }{12gx}+x/g )/x\\ T^{2}x=\frac{\pi^{2} L^{2} }{3g}+(\frac{4\pi^{2} }{g})x^{2}\\ 0=(\frac{4\pi^{2} }{g} )x^{2}-(T^{2} )x+(\frac{\pi^{2}L^{2} }{3g} )\\ 4.03x^{2}-23.04x+0.335=0$

After Solving this quadratic we get

x₁=5.702 m

x₂=0.01457 m

One of the solution is an impossible value for x (x=5.70m is greater than L)

So we choose the other one

x=0.01457 m

3 0

4 years ago

The prevailing winds that form in Hadley cells are _____.

dmitriy555 [2]

Answer = C

It blows towards the poles from the sub-tropical high pressure areas

8 0

3 years ago

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The reaction between magnesium (Mg) and oxygen (O2) forms magnesium oxide (MgO).

Scorpion4ik [409]

Answer:

2 Mg + O2 = 2MgO

Type: Synthesis

3 0

3 years ago