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Delvig [45]
3 years ago
15

What do we call living things that share characteristics including processes that make life possible?

Physics
2 answers:
RSB [31]3 years ago
7 0

Answer:

ORGANISMS

Explanation:

prohojiy [21]3 years ago
5 0
1. Organisms
2.animals &species
3.tree
True
Cell
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The peak value of an alternating current in a 1500-W device is 6.4 A. What is the rms voltage across it
horrorfan [7]

Answer:

6787.5 V

Explanation:

From the question,

P = IV..................... Equation 1

Where P = Power, I = rms current, V = rms voltage.

make V the subject of the equation

V = P/I................. Equation 2

Given: P = 1500 W, I = 6.4/√2 = 4.525 A

Substitute these values into equation 2

V = 1500(4.525)

V = 6787.5 V

Hence the rms voltage = 6787.5 V

7 0
3 years ago
An aluminum wing on a passenger jet is 35 m long when its temperature is 17°C. At what temperature would the wing be 3 cm (0.03
Mnenie [13.5K]

Answer:

53.32°C

Explanation:

Length of the aluminium wing = 35 m

Change in length of aluminium wing = 0.03 m

The linear expansion coefficient of aluminium \alpha =23.6\times 10^{-6}/^{\circ}C

We know that change in length is given by \Delta L=L\alpha \Delta T

So 0.03=35\times 23.6\times 10^{-6}\Delta T

\Delta T=36.32^{\circ}C

So final temperature =T_I+\Delta T=17+36.32=53.3196^{\circ}C

5 0
3 years ago
Calculate the amount of heat (in kj) required to raise the temperature of a 79.0 g sample of ethanol from 298.0 k to 385.0 k. th
earnstyle [38]
We are given with the specific heat capacity of ethanol, the mass of the sample and the temperature change to determine the total amount of heat to raise the temperature. The formula to be followed is H = mCpΔT. Upon subsituting, H = 79 g * 2.42 J/gC *(385-298)C = 16.63 kJ 
7 0
4 years ago
Which option defines green computing?
Papessa [141]
Study and practice of environmental sustainable computing or It. such as monitors, printers, storage devices, and networking and communication systems-efficiently and effectively with minimal impact on the environment.
4 0
3 years ago
Read 2 more answers
A beam of microwaves with λ = 0.9 mm is incident upon a 9 cm slit. At a distance of 1.5 m from the slit, what is the approximate
liq [111]

Answer:

3 cm

Explanation:

According to the question,

D=1.5 m.

d=9 cm.

\lambda =0.9 mm.

Now the approximate slit's image width is equal to width of central maxima.

And width of central maxima is twice the width from center to first maxima

So,

y=2\frac{\lambda (D)}{d}.

Substitute all the variable in above equation.

y=\frac{(2)0.9\times 10^{-2} m(1.5 m) }{0.09 m}.

y=3 cm.

5 0
3 years ago
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