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MA_775_DIABLO [31]
3 years ago
6

What can you infer about a wave with a short wavelength?

Physics
2 answers:
raketka [301]3 years ago
8 0

Answer:

- It can be infer that it has a lower frequency.

<em>In the case of electromagnetic waves.</em>

- A short wavelength means a lower energy,

Explanation:

The wavelength is the distance between two consecutive crests or valleys while the frequency is the number of crests that pass for a specific point in an interval of time.

For example, a person makes laundry once a weak.

In this example, the event is represented by the laundry and the interval of time is once a weak

The velocity of a wave is defined as:

v = \nu \cdot \lambda  (1)

Where nu is the frequency and \lambda is the wavelenth

\lambda =  \frac{v}{\nu}  (2)

Notice from equation 2 that the wavelength is inversely proportional to the frequency (when the wavelength increases the frequency decreases).

In the case of electromagnetic waves, a short wavelength means a lower energy, as it can be seen in equation 4 (inversely proportional).

E = h\nu  (3)

E = \frac{hc}{\lambda} (4)

garri49 [273]3 years ago
7 0

Answer:

The lesser the wavelength, the greater the frequency.

Explanation:

Let assume a mechanical wave with a certain wavelength propagating through a fluid, so that speed is that from sound. If wavelength is short, that is, wavelength is small, then frequency has a big value.

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A metal cube with sides of length a=1cm is moving at velocity v0→=1m/sj^ across a uniform magnetic field B0→=5Tk^. The cube is o
Nitella [24]

Answer:

the magnitude of the electric field is 1.25 N/C

Explanation:

The induced emf in the cube ε = LB.v where B = magnitude of electric field = 5 T , L = length of side of cube = 1 cm = 0.01 m and v = velocity of cube = 1 m/s

ε = LB.v = 0.01 m × 5 T × 1 m/s = 0.05 V

Also, induced emf in the cube ε = ∫E.ds around the loop of the cube where E = electric field in metal cube

ε = ∫E.ds

ε = Eds since E is always parallel to the side of the cube

= E∫ds  ∫ds = 4L since we have 4 sides

= E(4L)

= 4EL

So,4EL = 0.05 V

E = 0.05 V/4L

= 0.05 V/(4 × 0.01 m)

= 0.05 V/0.04 m

= 1.25 V/m

= 1.25 N/C

So, the magnitude of the electric field is 1.25 N/C

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Ctext%7BQUESTIONS%7D%7D%20%3A%20" id="TexFormula1" title=" \underline{
Musya8 [376]

Answer:

Solution given:

<u>any three applications of electromagnetic </u><u>waves</u><u> </u><u>are</u><u>:</u>

  1. <u>Used</u><u> </u><u>for</u><u> </u><u>cooking</u><u> </u><u>purpose</u><u> </u><u>in</u><u> </u><u>microwave</u><u>.</u>
  2. <u>Used</u><u> </u><u>in</u><u> </u><u>RADAR</u><u> </u><u>system</u><u> </u><u>for</u><u> </u><u>aircraft</u><u> </u><u>navigation</u><u>.</u>
  3. <u>Used</u><u> </u><u>in</u><u> </u><u>communication</u><u>.</u>

2.

Solution given;

power [P]=100W

Current [I]=5A.

Voltage [V]=?

we have

P=IV

100=5*V

V=\frac{100}{5}=<u>2</u><u>0</u><u>V</u>

<u>the voltage of the battery used in the </u><u>car</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u>V</u><u>.</u>

8 0
3 years ago
Read 2 more answers
A Hooke's law bowstring is stretched x meters until a force of f newtons is applied, and then held. By what factor will the elas
Liono4ka [1.6K]

The elastic potential energy increases by a factor of 9

Explanation:

The elastic potential energy of a bowstring is given by

E=\frac{1}{2}kx^2 (1)

where

k is the spring constant

x is the elongation of the bowstring

Hooke's law states the relationship between the force applied and the elongation of an elastic object:

F=kx

where

F is the force applied

x is the elongation

We can rewrite it as

x=\frac{F}{k}

And substituting into (1),

E=\frac{1}{2}k(\frac{F}{k})^2=\frac{F^2}{2k}

In  this problem, the force applied to the bowstring is tripled,

F' = 3F

So the final elastic potential energy is:

E'=\frac{(3F)^2}{2k}=9(\frac{F^2}{2k})=9E

So, the elastic potential energy increases by a factor of 9.

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

7 0
3 years ago
If an object accelerates from rest, with a constant acceleration of 4.4 m/s2, what will its velocity be after 28s?
Norma-Jean [14]

Answer:

123.2 m/s after 28s

Explanation:

Vi= 0 m/s

a= 4.4 m/s^2

t=28s

Vf after 28s

To find Vf use your kinematics formula Vf=Vi+at

Vi is Zero so it gets removed and the equation becomes

Vf=at  

Simply Plug and Solve

Vf= 4.4(28)

Vf=123.2 m/s after 28s

6 0
3 years ago
Question 9 please. How do you find instantaneous velocity and how do I sketch a velocity vs time graph from a position vs time o
pickupchik [31]

How do you find instantaneous velocity

Select a point on a distance-time curve graph. Draw a tangent to the curve at that point. Tangent -> hypotenuse of right angled triangle. Opp/adjacent in graph units is vel at that point -> in distance and/or time

3 0
4 years ago
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