You forgot to include the given line.
We need the given line to find the slope. The slope of parallel lines are equal. So, the slope of the line of the equation you are looking for is the same slope of the given line.
I can explain you the procedure to help you to find the desired equation:
1) Slope
Remember that the slope-intercept equation form is y = mx + b where m is the slope and b is thye y-intercept.
If you clear y in every equation you get:
a) y = (3/4)x + 17/4 => slope = 3/4
b) y = (3/4)x + 20/4 = (3/4)x + 5 => slope = 3/4
c) y = -(4/3)x - 2/3 => slope = -4/3
d) y = (-4/3)x - 6/3 = (-4/3)x - 2 => slope = -4/3
So, you just have to compare the slope of the given line with the above slopes to see which equations are candidates.
2) Point (-3,2)
You must verify which equations pass through the point (-3,2).
a) 3x - 4y = - 17
3(-3) - 4(2) = -17
- 9 - 8 = - 17
- 17 = - 17 => it is candidate
b) 3x - 4y = - 20
- 17 ≠ - 20 => it is not candidate
c) 4x + 3y = - 2
4(-3) + 3(2) = - 2
-12 + 6 = - 2
-6 ≠ -2 => it is not candidate
d) 4x + 3y = - 6
-6 = - 6 => it is candidate
3) So, the point (-3,2) permits to select two candidates
3x - 4y = - 17, and 4x + 3y = -6.
4) Yet you have to find the slope of the given equation, if it is 3/4 the solutions is the equation 3x - 4y = -17; if it is -4/3 the solution is the equation 4x + 3y = -6.
9514 1404 393
Answer:
25%
Step-by-step explanation:
The percentage is found by multiplying the fraction by 100%.
(oil changes)/(total cars) = 14/56 × 100% = 25%
25% of the cars received oil changes.
Answer:
Step-by-step explanation
- Amount of discount: 20%= 0.20; 0.20×42= $8.4
- Sale price: $42-$8.4= $33.6
For interest question, plug in the values:
P= $3200
r= 3%÷100 = 0.03
t= 4 years
Calculate:
I=Prt
= 3200×0.03×4
=$384
The answer is 12 J.
The kinetic energy (KE) of an object is expressed as the product of half of the mass (m) of the object and the square of its velocity (v²):
The unit of the kinetic energy is Joules (J = kg · (m/s)²).
It is given:
m = 1.5 kg
v = 4 m/s
It is unknown:
KE = ?
Thus:
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Therefore, the kinetic energy of the bird is 12J.
