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Leviafan [203]
3 years ago
7

Which statement is true about crystal lattice energy?

Physics
2 answers:
irinina [24]3 years ago
3 0

The answer is:

It is a measure of the strength of the bonds between ions.

Lattice energy is an estimate of the strength of the bonds formed by ionic compounds.

The first two choices are wrong because it is actually the opposite.

  • As the ion size increases, lattice energy <u>decreases</u>.
  • As charge of ions increases, lattice energy <u>increases</u>

As for the other third option, it is wrong because lattice energy is the energy RELEASED not absorbed.

BabaBlast [244]3 years ago
3 0

Answer: The correct option is:

It is a measure of the strength of the bonds between ions.

Explanation:

Lattice energy is defined as amount of energy released on the formation of one mole of crystalline solid from gaseous ions.It is also defined as energy required to break the 1 mole of crystalline solid into its constituting ions in gaseous state that is strength between the ions.

It depends upon two factors:

  • With increase in charge on the ion the lattice energy increases.
  • With increase in the size of the ions the lattice energy decreases.

So, from the given options the correct statement is:

It is a measure of the strength of the bonds between ions.

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the maximum range of a projectile is 2÷√3 times its actual range what is the angle of the projection for the actual range​
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Answer:

The actual angle is 30°

Explanation:

<h2>Equation of projectile:</h2><h2>y axis:</h2>

v_y(t)=vo*sin(A)-g*t

the velocity is Zero when the projectile reach in the maximum altitude:

0=vo-gt\\t=\frac{vo}{g}

When the time is vo/g the projectile are in the middle of the range.

<h2>x axis:</h2>

d_x(t)=vo*cos(A)*t\\

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R=d_x(t=2*\frac{vo}{g})

R=vo*cos(A)*2\frac{vo}{g} \\\\R=\frac{(vo)^{2}*2* sin(A)cos(A)}{g} \\\\R=\frac{(vo)^{2} sin(2A)}{g}

**sin(2A)=2sin(A)cos(A)

<h2>The maximum range occurs when A=45°(because sin(90°)=1)</h2><h2>The actual range R'=(2/√3)R:</h2>

Let B the actual angle of projectile

\frac{vo^{2} }{g} =(\frac{2}{\sqrt{3} }) \frac{vo^{2} *sin(2B)}{g}\\\\1= \frac{2 }{\sqrt{3}} *sin(2B)\\\\sin(2B)=\frac{\sqrt{3}}{2}\\\\

2B=60°

B=30°

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