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sammy [17]
3 years ago
5

A woman walks into a carpet store wearing high-heeled shoes with a circular heel of diameter 0.987 cm. To the dismay of the stor

e manager, she balances on one heel on an expensive carpet sample. If she has a mass of 53.0 kg, determine the pressure she exerts on the carpet sample.
Physics
1 answer:
jenyasd209 [6]3 years ago
3 0

To solve this problem it is necessary to apply the concepts related to the Pressure which describes the amount of Force made on an area unit.

Its mathematical expression can be defined as

P = \frac{F}{A}

Where,

F= Force

A = Area

Our values are given as

d = 0.987*10^{-2}m

With the diameter we can find the Area of the circular heel, that is

A = \pi (\frac{0.987*10^{-2}}{2})^2

A = 7.6511*10^{-5}m^2

To find the force by weight we need to apply the Newton's second Law

F = mg

F = 53*9.8

F = 519.4N

Finally the pressure would be

P = \frac{F}{A}

P = \frac{519.4}{7.6511*10^{-5}}

P = 6788566.35Pa

P = 6.788MPa

Therefore the pressure that she exerts on the carpet sample is 6.788Mpa

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Ad libitum [116K]

Answer:

Incomplete question check attachment for complete question

Also it is given that

q1=-0.7uC

q4=-1.7uC

q3=-1.7uC

Also the distance are given as

a=2.2cm=0.022m

d2=3.6cm=0.036m

Explanation:

The potential energy due to point R is given as

The potential energy due to charge q1 and q3 plus the potential energy due to charge q4 and q1 plus the potential energy due to charge q3 and q4

So, let take it one after the other

Potential energy is give as

P.E=kq1q2/r

Therefore,

Potential energy due to charge q1 and q3

U¹³=kq1q3/r

To get the distance between charge q1 and q3, we will apply Pythagoras theorem

r=√(d2²+a²)

r=√(0.036²+0.022²)

r=0.0422m

k is a constant =9×10^9Nm²/C²

Then,

U¹³=kq1q3/r

U¹³=9×10^9×0.7×10^-6×1.7×10^-6/0.0422

U¹³=0.254J

Potential energy due to charge q1 and q4

U¹⁴=kq1q4/r

To get the distance between charge q1 and q4, we will apply Pythagoras theorem

r=√(d2²+a²)

r=√(0.036²+0.022²)

r=0.0422m

k is a constant =9×10^9Nm²/C²

Then,

U¹⁴=kq1q4/r

U¹⁴=9×10^9×0.7×10^-6×1.7×10^-6/0.0422

U¹⁴=0.254J

Potential energy due to charge q3 and q4

U³⁴=kq3q4/r

r=2a=2×0.022=0.044m

k is a constant =9×10^9Nm²/C²

Then,

U³⁴=kq3q4/r

U³⁴=9×10^9×1.7×10^-6×1.7×10^-6/0.044

U¹⁴=0.591J

Then, the total energy is

U= U¹³+ U¹⁴ + U³⁴

U=0.254+0.254+0.591

U=1.099J

Then also, the potential energy is zero because at infinity both U¹³ and U¹⁴ will have infinite potential because their distance apart will be infinite.

6 0
3 years ago
It is not possible to convert work entirely into heat. It is impossible to transfer heat from a cooler to a hotter body. The sec
Irina-Kira [14]

Complete Question:

Which one of the following is a

true statement?

Group of answer choices.

A) The second law of thermodynamics is a consequence of the first law of thermodynamics.

B) It is possible for heat to flow spontaneously from a hot body to a cold one or from a cold one

to a hot one, depending on whether or not the process is reversible or irreversible.

C) It is not possible to convert work entirely into heat.

D) It is impossible to transfer heat from a cooler to a hotter body.

E) All of these statements are false.

Answer:

E) All of these statements are false.

Explanation:

All of the following statements are false;

I. The second law of thermodynamics is a consequence of the first law of thermodynamics. The second law of thermodynamics is about a physical quantity known as entropy while the first law of thermodynamics states that energy cannot be created or destroyed but can only be transformed from one form to another.

II. It is possible for heat to flow spontaneously from a hot body to a cold one or from a cold one

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III. It is not possible to convert work entirely into heat. It is possible to completely convert work into heat because it involves transferring energy.

IV. It is impossible to transfer heat from a cooler to a hotter body.

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Prototypes are often used in the final, testing phase in a Design Thinking process in order to determine how users behave with the prototype, to reveal new solutions to problems, or to find out whether or not the implemented solutions have been successful. The results generated from these tests are then used to redefine one or more of the problems established in the earlier phases of the project, and to build a more robust understanding of the problems users may face when interacting with the product in the intended environment.

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7 0
3 years ago
These are equal and opposite forces that do not cause a change in position or motion. True or False
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Answer:

TRUE

Explanation:

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This force is comprised of two most important properties namely the strength and direction. When any of the two forces is higher then it result in the motion of the object.

Thus, the above given statement is TRUE.

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