The atomic number for iodine (I) = 53
The electron for I is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵
Now, among the noble gases, Krypton (Kr) has an atomic number 36. Thus we can write:
I = [1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ ] 5s² 4d¹⁰ 5p⁵
I = [Kr] 5s² 4d¹⁰ 5p⁵
(or)
I = [Kr] 4d¹⁰ 5s² 5p⁵
Answer:
change of color of substance
Explanation:
I hope it helps
The correct answer among the choice listed is the third option. The reaction between silver nitrate and potassium hydroxide will yield a precipitate which is the silver hydroxide product. This is because this substance is not very soluble in aqueous solution.
Explanation:
Metals are the species which readily lose electrons in order to attain stability. This electron lost by the atom is actually present in its outermost shell which is also known as valence shell.
Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.
When we move across a period from left to right then there occurs a decrease in atomic size of the atoms. Therefore, ionization energy increases along a period.
But when we move down a group then there occurs an increase in atomic size of the atoms due to addition of number of electrons in the atoms. Hence, ionization energy decreases along a group.
Thus, we can conclude that metals have low ionization energies and readily share their valence or outer electrons with each other to form an electron sea. These electrons are delocalized or shared among all the atoms that are bonded together and can therefore move freely throughout the metal structure.