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erica [24]
3 years ago
5

6. How does surface area affect the rate of a reaction?

Chemistry
1 answer:
Katarina [22]3 years ago
8 0

Answer:

Increasing the Surface Area provides more opportunity for particles to collide and exhibit a <em>faster </em>reaction.

Increasing those collisions increases the rate of reactions that occur.

You might be interested in
Phosphorous pentoxide, P2O5(s), is produced from the reaction between pure oxygen and pure phosphorous (P, solid). What is the v
BartSMP [9]

Answer:

4190.22 L = 4.19 m³.

Explanation:

  • For the balanced reaction:

<em>2P₂ + 5O₂ ⇄ 2P₂O₅. </em>

It is clear that 2 mol of P₂ react with <em>5 mol of O₂ </em>to produce <em>2 mol of P₂O₅.</em>

  • Firstly, we need to calculate the no. of moles of 6.92 kilograms of P₂O₅ produced through the reaction:

no. of moles of P₂O₅ = mass/molar mass = (6920 g)/(283.88 g/mol) = 24.38 mol.

  • Now, we can find the no. of moles of O₂ is needed to produce the proposed amount of P₂O₅:

<u><em>Using cross multiplication:</em></u>

5 mol of O₂ is needed to produce → 2 mol of P₂O₅, from stichiometry.

??? mol of O₂ is needed to produce → 24.38 mol of P₂O₅.

∴ The no. of moles of O₂ needed = (5 mol)(24.38 mol)/(2 mol) = 60.95 mol.

  • Finally, we can get the volume of oxygen using the general law of ideal gas:<em> PV = nRT.</em>

where, P is the pressure of the gas in atm (P = 606.1 mm Hg/760 = 0.8 atm).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 60.95 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (396.90°C + 273 = 669.9 K).

∴ V of oxygen needed = nRT/P = (60.95 mol)(0.0821 L.atm/mol.K)(669.9 K)/(0.8 atm) = 4190.22 L/1000 = 4.19 m³.

3 0
3 years ago
While ethanol is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by reacting e
sp2606 [1]

The question is incomplete, here is the complete question:

While ethanol is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by reacting ethylene with water vapor at elevated temperatures.

A chemical engineer studying this reaction fills a 1.5 L flask at 12°C with 1.8 atm of ethylene gas and 4.7 atm of water vapor. When the mixture has come to equilibrium she determines that it contains 1.16 atm of ethylene gas and 4.06 atm of water vapor.

The engineer then adds another 1.2 atm of ethylene, and allows the mixture to come to equilibrium again. Calculate the pressure of ethanol after equilibrium is reached the second time. Round your answer to 2 significant digits.

<u>Answer:</u> The partial pressure of ethanol after equilibrium is reached the second time is 1.0 atm

<u>Explanation:</u>

We are given:

Initial partial pressure of ethylene gas = 1.8 atm

Initial partial pressure of water vapor = 4.7 atm

Equilibrium partial pressure of ethylene gas = 1.16 atm

Equilibrium partial pressure of water vapor = 4.06 atm

The chemical equation for the reaction of ethylene gas and water vapor follows:

                     CH_2CH_2(g)+H_2O(g)\rightleftharpoons CH_3CH_2OH(g)

<u>Initial:</u>                  1.8                4.7

<u>At eqllm:</u>           1.8-x             4.7-x

Evaluating the value of 'x'

\Rightarrow (1.8-x)=1.16\\\\x=0.64

The expression of K_p for above equation follows:

K_p=\frac{p_{CH_3CH_2OH}}{p_{CH_2CH_2}\times p_{H_2O}}

p_{CH_2CH_2}=1.16atm\\p_{H_2O}=4.06atm\\p_{CH_3CH_2OH}=0.64atm

Putting values in above expression, we get:

K_p=\frac{0.64}{1.16\times 4.06}\\\\K_p=0.136

When more ethylene is added, the equilibrium gets re-established.

Partial pressure of ethylene added = 1.2 atm

                     CH_2CH_2(g)+H_2O(g)\rightleftharpoons CH_3CH_2OH(g)

<u>Initial:</u>                2.36             4.06               0.64

<u>At eqllm:</u>           2.36-x        4.06-x             0.64+x

Putting value in the equilibrium constant expression, we get:

0.136=\frac{(0.64+x)}{(2.36-x)\times (4.06-x)}\\\\x=0.363,13.41

Neglecting the value of x = 13.41 because equilibrium partial pressure of ethylene and water vapor will become negative, which is not possible.

So, equilibrium partial pressure of ethanol = (0.64 + x) = (0.64 + 0.363) = 1.003 atm

Hence, the partial pressure of ethanol after equilibrium is reached the second time is 1.0 atm

3 0
3 years ago
What is the major organic product obtained from the reaction of ethylbenzene with nitronium ion, followed by benzylic oxidation?
Degger [83]

Answer:

b

Explanation:

8 0
3 years ago
discuss how variations in electronegativity result in the unequal sharing of electrons in polar molecules.
konstantin123 [22]

Variations in electronegativity prompt in the unequal halves of electrons in polar molecules because when one atom is more electronegative than the other, it becomes more polar than the other.

It results in the more electronegative atom to have a slightly negative (-ve) charges, and the other atom to have partial or slightly positive(+ve) charges.

Polar molecules have unequal sharing of electrons because the atoms have unequal attraction for electrons so the sharing is unequal.

The larger the difference in electronegativity between the two atoms, the more the polar the bond.

Hydrogen bonds are involved in unequal sharing of electrons between two atoms.

To know more about variations in electronegativity in polar molecules here :

brainly.com/question/18260584?referrer=searchResults

#SPJ4

6 0
2 years ago
Un átomo neutro tiene número atómico 1 y número másico 3. Indica cuántos protones, neutrones y electrones tiene.
ahrayia [7]

Answer:

El átomo podes 1 protón, 1 electrón y 2 neutrones.

Explanation:

Cada elemento químico se caracteriza por el número de protones de su núcleo, que se denomina número atómico Z. Es decir, el número atómico​ de un elemento químico es el número total de protones que tiene cada átomo de ese elemento.

Los protones poseen carga positiva y se encuentran en el núcleo, en torno al cual se mueven otras partículas con carga eléctrica negativa que son los electrones. Así, el átomo es eléctricamente neutro, ya que la carga positiva de los protones está compensada por la carga negativa de los electrones.  Entonces, en todo átomo neutro el número de protones del núcleo es igual al de electrones de sus orbitales.

En este caso, un átomo neutro tiene número atómico 1. Entonces la cantidad de protones y electrones presentes en el átomo es 1.

En el núcleo de cada elemento, además de protones, también es posible encontrar neutrones, cuyo número puede variar. La masa atómica (A) se obtiene sumando el número de protones y de neutrones de un núcleo determinado:

Número másico (A) = número de protones + número de neutrones

En este caso, el átomo neutro posee 1 protón y su número másico es 3. Entonces:

3= 1 + número de neutrones

Resolviendo:

3 - 1= número de neutrones

2= número de neutrones

Entonces,<u><em> el átomo podes 1 protón, 1 electrón y 2 neutrones.</em></u>

6 0
3 years ago
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