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erica [24]
3 years ago
5

6. How does surface area affect the rate of a reaction?

Chemistry
1 answer:
Katarina [22]3 years ago
8 0

Answer:

Increasing the Surface Area provides more opportunity for particles to collide and exhibit a <em>faster </em>reaction.

Increasing those collisions increases the rate of reactions that occur.

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Pls help!!! I will mark you as brainliest if you answer the question!!
SVEN [57.7K]

1 — Element D and A ( Which are Sodium and aluminium )

2 — ( 2 + 8 + 3 = 13 electrons total ) Element A Because it's atomic number is 13.

3 — Element E Is stable. ( Which is Argon )

( Note, Elements which has 8 election on its outermost cell is stable. ( Helium is exception which is a noble gas but have 2 electrons in outermost cell )

4 — Element F , which is hydrogen. ( Hydrogen is the only element to not have any neutron )

5 — Element D ( Which is sodium )

6 — The element F ( Which is hydrogen ) Don't contain any neutron.

________________________________

5 0
3 years ago
When the absolute value of the difference in electronegativity of two adjacent atom in a compound is 1, they are most likely bon
Morgarella [4.7K]

Answer:polar covalent bond

Explanation:

Compounds are formed ether by donating, receiving or sharing of electrons making the bonds between them to  be ionic, or covalent .

Now  according to the rule  of type of bond assignment due to electronegativity difference of atoms

---When the  electronegativity difference is less than 0.5,  the bond formed is nonpolar covalent.

---When   the  electronegativity difference is between 0.5 and 1.6, the bond is considered polar covalent

---When  the  electronegativity difference greater than 2.0, then the bond is ionic.

Therefore, When the absolute value of the difference in electronegativity of two adjacent atom in a compound is 1, they are most likely bonded by  polar covalent bond eg HCl bond , CCL4 bond

8 0
3 years ago
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blagie [28]

Answer:

False

Explanation:

3 0
3 years ago
Read 2 more answers
If you complete and balance the following oxidation-reduction reaction in basic solution NO2−(aq) + Al(s) → NH3(aq) + Al(OH)4−(a
andreev551 [17]

Answer:

NO2- + 5H2O + 2Al + OH- → NH3 + 2Al(OH)4-

There is 1 hydroxide ion, on the reactant side

Explanation:

NO2−(aq) + Al(s) → NH3(aq) + Al(OH)4−(aq)

Step 1: The half reactions

NO2- (aq) → NH3(g)

Al(s) → Al(OH)4-

<u>Step 2: </u>Balancing electrons

NO2- → NH3

On the left side N has an oxidation number of +3 and on the right side -3.

NO2- +6e-→ NH3

Al(s) → Al(OH)4-

On the left side, Al has an oxidation number of 0 and on the right side +3.

Al(s) → Al(OH)4- +3e-

To have the same amount of electrons transfered, we have to multiply the second reaction by 2

NO2- +6e-→ NH3

2(Al(s) → Al(OH)4- +6e-)

<u>Step 3:</u> Balance with OH/H2O

NO2- +6e +5H2O → NH3 +7OH-

2Al +8OH- → 2Al(OH)4- + 6e-

<u>Step 4:</u> The netto reaction

NO2- + 5H2O + 2Al + 8OH-  → NH3 +7OH- + 2Al(OH)4-

NO2- + 5H2O + 2Al + OH- → NH3 + 2Al(OH)4-

There is 1 hydroxide ion, on the reactant side

6 0
4 years ago
Butane gas (C4H10) burns in oxygen gas to produce carbon dioxide gas and water vapor. Balance the equation for this reaction (in
bixtya [17]

Answer:

C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)

2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)

Explanation:

Butane gas (C₄H₁₀) burns in oxygen gas to produce carbon dioxide gas and water vapor. The unbalanced equation is:

C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)

First, we will balance carbon and hydrogen which are in just one compound on each side.

C₄H₁₀(g) + O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)

Finally, we will balance the oxygen atoms.

C₄H₁₀(g) + 6.5 O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)

In order to have integers, we will multiply everý compound by 2.

2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)

5 0
4 years ago
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