Answer:
an object at motation tends to stay in motion unless acted upon a nother object and an object at rest tends to stay at rest unless acted upon a nother object
Explanation:
Answer:
radial acceleration is 41.8 m / s²
Explanation:
The acceleration for circular motion is
a = v² / r
They also give us the X and Y position where the body falls when the rope breaks, let's write the projectile launch equations
x = vox t
y = v₀ₓ t - ½ g t2
Since the circle is horizontally the v₀ₓ is zero (v₀ₓ = 0)
x = v₀ₓ t
t = x / v₀ₓ
y = - ½ g t²
Let's replace and calculate the initial velocity on the X axis
y = - ½ g (x / vox)²
v₀ₓ = √ (g x² / 2 y)
v₀ₓ = √ [- (-9.8) 1.6² / (2 1.00)]
v₀ₓ = 3.54 m / s
This is the horizontal velocity, but since it circle is in horizontal position it is also the velocity of the body at the point of rupture.
Now we can calculate the radial acceleration
a = v² / r
a = 3.54² / 0.300
a = 41.8 m / s²
Answer:
<h3>The answer is 3.81 kg</h3>
Explanation:
The mass of the dog can be found by using the formula

f is the force
a is the acceleration
From the question we have

We have the final answer as
<h3>3.81 kg</h3>
Hope this helps you
Explanation:
i really didn't understand the question
im soo so sorry