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nlexa [21]
3 years ago
8

Even, in 1921, the Dodge Brothers built a boat named the SS Delphine and it had a whopping 3000 HP. So, how much horsepower woul

d a Challenger SRT® Hellcat Redeye Widebody need to tow the SS Delphine up the industry standard: Davis Dam Grade Climb?
Physics
2 answers:
satela [25.4K]3 years ago
7 0

Answer: I am getting a result around the 54,800 area, so I am selecting the 55,000 HP answer.

dmitriy555 [2]3 years ago
6 0

Answer:

θ = tan-1(.07) = 4.004172941 deg.

F(rr) = 4076451 lbf * 0.015 * cos(4.004172941) = 60997.50 lbf

F(w) = 4076451 lbf * sin(4.004172941) = 284655.02 lbf

Fsum = 6433 + 60997.5 + 284655.02 = 352085.82 lbf

P = 352085.82 lbf * 59 ft/s = 20773063.27 ft*lbf/s

HP = (20773063.27 ft*lbf/s) * (1 hp / 550 ft*lbf/s) = 37,769.206 hp <> 37,737 hp

Your answer is 37,737

Hope this helps :) -Mark Brainiest Please :)

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Charge A and charge B are 2.2 m apart. Charge A is 1.0 C, and charge B is
Ipatiy [6.2K]

Its really hurts

Explanation:

Charge A and charge B are 2.2 m apart. Charge A is 1.0 C, and charge B is

2.0 C. Charge C, which is 2.0 C, is located between them and is in

electrostatic equilibrium. How far from charge A is charge C?

6 0
3 years ago
A satellite orbits earth with a mean altitude of 361 km. If the orbit is circular, what are the satellite's time period and spee
Advocard [28]

Answer:

v = 7.69 x 10³ m/s = 7690 m/s

T = 5500 s = 91.67 min = 1.53 h

Explanation:

In order for the satellite to orbit the earth, the force of gravitation on satellite must be equal to the centripetal force acting on it:

F_{gravitation}= F_{centripetal}\\\\\frac{GM_{s} M_{E}}{r^2}  = \frac{M_{s} v^2}{r}\\\\\frac{GM_{E}}{r} = v^2\\\\v = \sqrt{\frac{GM_{E}}{r} } \\\\

where,

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

Me = Mass of Earth = 5.97 x 10²⁴ kg

r = distance between the center of Earth and Satellite = Radius of Earth + Altitude = 6.371 x 10⁶ m + 0.361 x 10⁶ m = 6.732 x 10⁶ m

v = orbital speed = ?

Therefore,

v = \sqrt{\frac{(6.67 x 10^{-11}N.m^2/kg^2)(5.97 x 10^{24} kg)}{6.732 x 10^6 m} }\\\\

<u>v = 7.69 x 10³ m/s</u>

For time period satellite completes one revolution around the earth. It means that the distance covered by satellite is equal to circumference of circle at the given altitude.

So, its orbital speed can be given as:

v = \frac{Circumference of Circle at Given Altitude}{T}\\\\v =  \frac{2\pi r}{T}\\\\

where,

T = Time Period of Satellite = ?

Therefore,

T = \frac{2\pi r}{v}\\\\T = \frac{(2\pi )(6.732 x 10^6 m}{7.69 x 10^3 m/s}\\\\

<u>T = 5500 s = 91.67 min = 1.53 h</u>

7 0
3 years ago
A tennis racket strikes a tennis ball with a force of 100 N. With what force
viva [34]

Answer:

-100N

Explanation:

Newton's third law of motion states that to every force exerted on one body, there is an equal and opposite force. This means that if object A exerts an ACTION force on B, there is a force called REACTION FORCE, which is equal and opposite, exerted on A by B.

The action and reaction forces are equal in size/magnitude but opposite in direction. In this case where a tennis racket strikes a tennis ball with a force (action force) of 100N, the ball will strike the racket with a reaction force of -100N.

F(RB) = -F(BR)

8 0
3 years ago
A mass of 250 N is on a piston of 2.0 m^2. What force is needed to lift this piston if the area of the second piston is 0.5 m^2?
prohojiy [21]

Answer:

<h3>62.5N</h3>

Explanation:

The pressure at one end of the piston is equal to the pressure on the second piston.

Pressure = Force/Area

F1/A1 = F2/A2

Given

F1 = 250N

A1 = 2.0m²

A2 = 0.5m²

F2 = ?

Substituting the given values in the formula;

250/2 = F2/0.5

cross multiply

250*0.5 = 2F2

125 = 2F2

F2 = 125/2

F2 = 62.5N

Hence the  force needed to lift this piston if the area of the second piston is 0.5 m^2 is 62.5N

8 0
3 years ago
From the lens equation calculate the position of the following images produced by a convex lens.
fiasKO [112]

Explanation:

(i)

O is the object and I is the image.

The image formed is enlarged and it is erect. So the magnification will be positive (+) and greater than 1.

Refer above image. 1

(ii)

O is the object and I is the image.

The image formed is diminished and erect. So the magnification will be positive (+) and less than1.

Refer above image. 2

(iii)

The image will be formed as the 2F on the other side of the lens and it will be of same of the object.

5 0
3 years ago
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