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nlexa [21]
3 years ago
8

Even, in 1921, the Dodge Brothers built a boat named the SS Delphine and it had a whopping 3000 HP. So, how much horsepower woul

d a Challenger SRT® Hellcat Redeye Widebody need to tow the SS Delphine up the industry standard: Davis Dam Grade Climb?
Physics
2 answers:
satela [25.4K]3 years ago
7 0

Answer: I am getting a result around the 54,800 area, so I am selecting the 55,000 HP answer.

dmitriy555 [2]3 years ago
6 0

Answer:

θ = tan-1(.07) = 4.004172941 deg.

F(rr) = 4076451 lbf * 0.015 * cos(4.004172941) = 60997.50 lbf

F(w) = 4076451 lbf * sin(4.004172941) = 284655.02 lbf

Fsum = 6433 + 60997.5 + 284655.02 = 352085.82 lbf

P = 352085.82 lbf * 59 ft/s = 20773063.27 ft*lbf/s

HP = (20773063.27 ft*lbf/s) * (1 hp / 550 ft*lbf/s) = 37,769.206 hp <> 37,737 hp

Your answer is 37,737

Hope this helps :) -Mark Brainiest Please :)

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Newton's first law states that an object in motion tends to. An object a rest tends to
Arturiano [62]

Answer:

an object at motation tends to stay in motion unless acted upon a nother object and an object at rest tends to stay at rest unless acted upon a nother object

Explanation:

8 0
3 years ago
A ball on the end of a string is whirled around in a horizontal circle of radius 0.300 m. The plane of the circle is 1.00 m abov
Mamont248 [21]

Answer:

radial acceleration is 41.8 m / s²

Explanation:

The acceleration for circular motion is

     a = v² / r

They also give us the X and Y position where the body falls when the rope breaks, let's write the projectile launch equations

     x = vox t

     y = v₀ₓ t - ½ g t2

Since the circle is horizontally the v₀ₓ is zero (v₀ₓ = 0)

     x = v₀ₓ t

     t = x / v₀ₓ

     y = - ½ g t²

Let's replace and calculate the initial velocity on the X axis

    y = - ½ g (x / vox)²

    v₀ₓ = √ (g x² / 2 y)

    v₀ₓ = √ [- (-9.8) 1.6² / (2 1.00)]

    v₀ₓ = 3.54 m / s

This is the horizontal velocity, but since it circle is in  horizontal position it is also the velocity of the body at the point of rupture.

Now we can calculate the radial acceleration

        a = v² / r

       a = 3.54² / 0.300

       a = 41.8 m / s²

5 0
3 years ago
If a dog is accelerating at a constant rate of 6.57 m/s2, what is the mass of the dog if 25 N of force is being applied to it?
Oliga [24]

Answer:

<h3>The answer is 3.81 kg</h3>

Explanation:

The mass of the dog can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{25}{6.57}  \\  = 3.80517503

We have the final answer as

<h3>3.81 kg</h3>

Hope this helps you

8 0
3 years ago
Hellppppp&amp;/&amp;/&amp;/&amp;//&amp;/&amp;/&amp;/&amp;/&amp;&amp; will give brainiest
Komok [63]

Explanation:

i really didn't understand the question

im soo so sorry

3 0
3 years ago
Ayuda por favor cual es el objetivo del ultimate?
postnew [5]

Answer: i d k

Explanation:

3 0
3 years ago
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