3 years ago

A foce that pushes or pulls is known as

Chemistry

1 answer:

Radda [10]3 years ago

3 0

Answer:

Newton 3rd Law of Motion or the Law of Force Pairs

(An applied force)

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Read 2 more answers

I'm not 100% sure of the answer. Explanations are highly appreciated.

PolarNik [594]

Answer:

The correct answer is

$\Delta H=2(1072)+498 -4(799)$

Explanation:

Enthalpy of reaction :

It is the amount of energy released/absorbed when one mole of the substance is formed from the reactant at a constant pressure.

The enthalpy of a reaction can be calculated using :

$\Delta H=\Delta H_{reactants}-\Delta H_{products}$

$2CO+O_{2}\rightarrow 2CO_{2}$

$\Delta H_{reactants}=2(C\equiv O)+O=O$

$\Delta H_{reactants}=2(1072)+498$

$H_{products}=2(2\times C=O)$

$H_{products}=4\times 799$

$\Delta H=\Delta H_{reactants}-\Delta H_{products}$

$\Delta H=2(1072)+498 -4(799)$

$units = \frac{kJ}{mole}$

Please note that :

The carbon monoxide , CO should be taken as C triple bond O. Not C=O .

So , the bond energy =1072 is used

$\Delta H=2(1072)+498 -4(799)$

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3 years ago

A foce that pushes or pulls is known as​

A foce that pushes or pulls is known as