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Nezavi [6.7K]
2 years ago
14

A manual contains instructions for how to build a variety of structures using a set of interlocking bricks. If this scenario is

used as a model for genetic information, which statement is correct?(1 point)
Each set of instructions is a protein.
Each set of instructions is a protein.

The manual is a chromosome.
The manual is a chromosome.

The interlocking bricks are the chromosomes.
The interlocking bricks are the chromosomes.

Each structure is a gene.
Each structure is a gene.
Chemistry
1 answer:
elena-14-01-66 [18.8K]2 years ago
3 0

If this scenario is used as a model for genetic information, then the statement 'the manual is a chromosome' is correct. A chromosome contains linear arrangements of genes.

<h3>What is a chromosome?</h3>

A chromosome can be considered as a long nucleotide sequence that contains linear arrangements of genes.

In a chromosome, each DNA strand contains a nucleotide sequence that may encode proteins (i.e., different genes).

A chromosome can then be considered as manual containing instructions (genes) for how to build a variety of structures using a set of interlocking bricks (nucleotides).

Learn more about chromosomes and genes here:

brainly.com/question/16218625

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A student needs to convert a volume of 3 Tbsp (tablespoons) to mL. The student finds out that 1 tablespoon is equivalent to 14.7
garri49 [273]

Answer:

The conversion factor is 14.79 mL/Tbsp.

Explanation:

To do an unity conversiton, we can make a factor by a ratio transformation:

3 Tbsp * \frac{14.79 mL}{1Tbsp}

So, the conversion factor is 14.79 mL/Tbsp and 3 Tbsp has 44.37 mL.

3 0
3 years ago
Ca(s) + O₂(g) + S(s) → CaSO4(s)
san4es73 [151]

The mass of Calcium required to complete this reaction is 4.008 g.

  • Law of conservation of mass states that In a closed system, mass cannot be produced or destroyed, but it can be changed from one form to another.
  • The mass of the chemical constituents before a chemical reaction is equal to the mass of the constituents after the reaction.
  • In several disciplines, including chemistry, mechanics, and fluid dynamics, the idea of mass conservation is widely applied.

In the given reaction mass of product after completion of reaction is 13.614 g that means total mass of constituents before reaction should also be 13.614.

So,

mass of Ca + mass of O₂ + mass of S = mass of CaSO4

Ca + 6.400 g + 3.206 g = 13.614 g

mass of Ca = 13.614 - 9.606 = 4.008 g

Therefore, by law of conservation of mass 4.008 g of Ca is required for the completion of the reaction.

Learn more about mass conservation here:

brainly.com/question/2030891

#SPJ9

5 0
1 year ago
Which of the following is not a function?
EastWind [94]

Answer:

A student's name paired with the sport that they play.​

Explanation:

8 0
3 years ago
When something is in the incorrect to state that a compound is broken down into its component elements in a decomposition reacti
zzz [600]
.........................
7 0
3 years ago
The thallium (present as Tl2SO4) in a 9.486-g pesticide sample was precipitated as thallium(I) iodide. Calculate the mass percen
tino4ka555 [31]

Answer: The mass percentage of Tl_2SO_4 is 5.86%

Explanation:

To calculate the mass percentage of Tl_2SO_4 in the sample it is necessary to know the mass of the solute (Tl_2SO_4 in this case), and the mass of the solution (pesticide sample, whose mass is explicit in the letter of the problem).

To calculate the mass of the solute, we must take the mass of the TlI precipitate.  We can establish a relation between the mass of TlI and Tl_2SO_4 using the stoichiometry of the compounds:

moles\ of\ TlI = \frac{0.1824 g}{331.27\frac{g}{mol} } = 5.51*10^{-4}\ mol.

Since for every mole of Tl in TlI there are two moles of Tl in Tl_2SO_4, we have:

moles\ of\ Tl_2SO_4 = 2 * moles\ of\ TlI = 1,102*10^{-3}\ mol

Using the molar mass of Tl_2SO_4 we have:

mass\ of\ Tl_2SO_4 = 1,102*10^{-3}\ mol * 504.83\ \frac{g}{mol}= 0.56\ g

Finally, we can use the mass percentage formula:

mass\ percentage = (\frac{solute\ mass}{solution\ mass} )*100 = (\frac{mass\ of\ Tl_2SO_4}{pesticide\ sample\ mass})*100 = (\frac{0.56g}{9.486g})*100 = 5.86\%

6 0
3 years ago
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