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const2013 [10]
3 years ago
13

I need help putting these in order . Someone Please help me .

Chemistry
1 answer:
Lynna [10]3 years ago
4 0

By lowering temperature from liquid to solid, atoms lose some of their energy, when atoms slow down, they move close together and make the matter denser.

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2AgNO3 + BaCl2 → 2AgCl + Ba(NO3)2
miv72 [106K]
<h3>Answer:</h3>

4 g AgCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN]   2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂

[Given]   5.0 g AgNO₃

<u>Step 2: Identify Conversions</u>

[Reaction - Stoich] 2AgNO₃ → 2AgCl

Molar Mass of Ag - 107.87 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                              \displaystyle 5.0 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{2 \ mol \ AgCl}{2 \ mol \ AgNO_3})(\frac{143.22 \ g \ AgCl}{1 \ mol \ AgCl})
  2. Multiply/Divide:                                                                                                  \displaystyle 4.21533 \ g \ AgCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

4.21533 g AgCl ≈ 4 g AgCl

3 0
3 years ago
In 1911 Ernest Rutherford did a famous experiment using fast-moving alpha particles as bullets and very thin gold foil as a targ
Roman55 [17]
1. Atoms are mostly empty space

2. Atoms have a concentration of positive matter somewhere in them

3. The concentration of this positive matter is very small
7 0
2 years ago
Given the chemical formulas of the following compounds, name each compound and state the rules you used to determine each name.
jeka57 [31]
The name of the compound Na2SO4 is:
nitrogen sulfite
nitrogen sulfide
sodium sulfate
sodium sulfite
nickel sulfide

sodium sulfate


The formula of calcium phosphate is:
CaPO4
CaP
Ca3(PO4)2
Ca4(PO4)3
Ca(PO4)2

Ca3(PO4)2


The formula for calcium acetate is:
Ca2C2H3O2
CaC2O4
Ca(C2O4)2
Ca(C2H3O2)2
CaC2H3O2

Ca(C2H3O2)2


5 0
3 years ago
A) How much CO is required for the production of Fe from 1000 tonnes of magnetite (Fe2O4). Assume that the iron ore is 100% pure
Kryger [21]
Its b im pretty sure
5 0
3 years ago
A rigid cylinder with a movable piston contains a sample of gas. At 300. K, this sample has a pressure of 240. Kilopascals and a
iren [92.7K]

Answer:

The volume of this sample when the temperature is changed to 150 K and the pressure is changed to 160 kPa is 52.5 mL.

Explanation:

Boyle's law says that: "The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure" and is expressed mathematically as:

P * V = k

where k is a constant.

Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure, by means of a constant of proportionality that is applied directly. So Charles's law is a law that mathematically says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T}=k

Gay-Lussac's law states that the pressure of a fixed volume of a gas is directly proportional to its temperature. In other words, if the volume of a certain quantity of ideal gas remains constant, the quotient between pressure and temperature remains constant:

\frac{P}{T}=k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T}=k

Considering an initial state 1 and a final state 2, it is satisfied:

\frac{P1*V1}{T1}=\frac{P2*V2}{T2}

In this case:

  • P1: 240 kPa
  • V1: 70 mL
  • T1: 300 K
  • P2: 160 kPa
  • V2: ?
  • T2: 150 K

Replacing:

\frac{240 kPa*70 mL}{300 K}=\frac{160 kPa*V2}{150 K}

Solving:

V2=\frac{150 K}{160 kPa} *\frac{240 kPa*70 mL}{300 K}

V2= 52.5 mL

<u><em>The volume of this sample when the temperature is changed to 150 K and the pressure is changed to 160 kPa is 52.5 mL.</em></u>

6 0
4 years ago
Read 2 more answers
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