Nswer
<span>Work done = Pressure * ΔV [ change in volume ] </span>
<span>If ΔV=0, then no work is done </span>
<span>Zero work thermodyanamic process is called ' isochoric process.' </span>
<span>For example if a gas heated in a rigid container: the pressure and temperature </span>
<span>of the gas will increase, but the volume will remain the same. </span>
<span>This is called an isochoric thermodynamic process. </span>
<span>It is actually possible to do work on a system without changing the </span>
<span>volume, as in the case of stirring a liquid</span>
Answer:
Ffriction = 90 N
coefficient = 0.3
Explanation:
First, note that the sum of all the forces in the x directions equals the mass multiplied by the acceleration in the x direction.
assuming the direction of the pulling force is positive,
243 N - Ffriction = m * a
m= 30.6 kg
a= 5 m/s/s
Ffriction= 243 - m*a
Ffriction= 243 - (30.6)(5)
Ffriction=90 N
The force of friction is equal to the coefficient of friction multiplied by the normal force on the object. Because the pulling force is completely horizontal, the normal force of the object is equal to its weight, which is m * g, or (30.6 kg)(9.8 m/s/s) = 299.88 N
Ffriction = coefficient * Fnormal
90 = coefficient * 299.88
coefficient = 0.3
-- Top picture:
'a' and 'b' have the same magnitude, and both are positively charged.
-- Bottom picture:
The charge on the particle is negative.
Answer:All the forces are acting. The force due to which the car stops that is between road and tire is "friction".
Explanation:
Answer:
Angular velocity of merry-go-round is πk - 1 at t= T
Explanation:
From the question it is given that
..........................(1)
since mathematically, angular velocity is defined as
........................(2)
on substituing the value of θ(t) from equation 1 in equation (2) we get
= 
............................(3)
on differentiating equation (3) with respect to time we get
ω(t) = πk(1 -
) = πk - 1 angular velocity of merry-go-round
Therefore, angular velocity of merry-go-round is πk - 1 at t= T
