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sergij07 [2.7K]
3 years ago
8

PLEASEE HELPP MEEE WITH NUMBER 5!!!!!! please explain why!!!!

Chemistry
1 answer:
V125BC [204]3 years ago
6 0

Answer:

Asexual, they don't require a mate and the mate may have genes that could change the way the plant looks or lives.

Explanation:

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Which experimental feature of the MALDI-MS technique allows the separation of ions formed after the adduction of tissue molecule
34kurt

Answer:

The experimental feature of the MALDI-MS technique which allows the separation of ions formed after the adduction of tissue molecules:

B) Velocity of ions depends on the ion mass-to-charge ratio.

Explanation:

  • The option a is not correct as distance traveled by ions doesn't depend upon the ion charge rather it depends upon time for which you leave the sample to run.
  • The  option b is correct as velocity of ions depends on the ion mass-to-charge ratio because separation is done due to mass to charge ratio feature.
  • The option c is incorrect as time of travel is not inversely proportional to the ion-to-mass ratio because the ion will move across the gel until you stop the electric field.
  • The option d is not correct as electric field between MALDI plate and MS analyzer is though uniform but this feature doesn't allow the separation of ions.

6 0
3 years ago
A coke has a ph of 3.5. this means that it has an excess of _______ ions and would be called a(n) _____.
Anuta_ua [19.1K]
PH (potential of hydrogen) is a numeric scale that is used to show the acidity or basicity of an aqueous solution. It tells how acidic or alkaline a substance is . The pH values ranges from 0 to 14, such that acidic solutions have values between 1 to 6.9 with most acidic having a pH value of 1 and those that are basic have values from 7.1 to 14, with most acidic having a value of 14. Acidic compounds contain replaceable hydrogen ions while basic compounds contain hrdroxyl ions. In this case, a coke has a pH of 3.5 (acidic) which means that it has an excess of hydrogen ions (H+) and would be called an acid.
3 0
3 years ago
Read 2 more answers
The product of the nuclear reaction in which 40Ar is subjected to neutron capture followed by alpha emission is ________. The pr
Orlov [11]

Answer:

37S

Explanation:

Radioactivity is the spontaneous emission of particles and / or electromagnetic radiation by unstable atomic nuclei leading to their disintegration.

We have two main types of radioactivity: radioactive decay and artificial transmutation.

In radioactive decay ( natural radioactivity ), a naturally occurring radioactive element like Uranium-238 disintegrates or decays into more stable isotopes with the emission of particles and/or radiation.

23892U = 23490Th + 42He

Artificial transmutation is the collision of two particles where one particle captures the other used to bombard it. There is subsequent production of isotopes similar or different from the bombarded particle. Neutrons, alpha particles ( helium nucleus ), electrons, protons can be used to bombard elements.

147N + 42He = 178O + 11P

For the above question which is artificial transmutation, the reaction equation is

4018Ar + 10n = 3716S + 42He

So, the neutron capture by Argon-40 will produce a radioisotope Sulphur-37 with the emission of an alpha particle.

5 0
3 years ago
Can someone help? <br><br> Name the compound:
Serhud [2]

CH=benzene

Why?

benzene is represented by the empirical formula CH, which indicates that a typical sample of the compound contains one atom of carbon (C) to one atom of hydrogen (H).

----(<em>Is</em><em> </em><em>this</em><em> </em><em>what</em><em> </em><em>you</em><em> </em><em>meant</em><em>?</em><em>?</em><em>?</em><em>)</em>

5 0
2 years ago
A sample of argon initially has a volume of 5.0 L and the pressure is 2 atm. If the final temperature is 30° C, the final volume
jenyasd209 [6]
Volume of Argon V1 = 5.0 L  
Pressure of Argon P1 = 2 atm 
Final temperature T2 = 30 C = 30 + 273 = 303 K 
Volume at final temperature V2= 6 L 
Pressure at final temperature P2 = 8 atm  
We know that (P1 x V1) / T1 = (P2 x V2) / T2  
(2 x 5)/ T1 = (8 x 6)/ 303 => T1 = (10 x 303) / 48 
Initial Temperature T1 = 3030 / 48 = 63.12 
Initial Temperature = -209. 8 C
4 0
3 years ago
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