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LuckyWell [14K]
3 years ago
5

Which statement is true about trends in metallic character?a) Metallic character increases as you go to the right across a row i

n the periodic table and as you go down a column.b) Metallic character decreases as you go to the right across a row in the periodic table and increases as you go down a column.c) Metallic character decreases as you go to the right across right across a row in the periodic table and decreases as you go down a columnd) Metallic characterdecreases as you go to the right across a row in the periodic table and increases as you go down a column
Chemistry
1 answer:
klasskru [66]3 years ago
6 0

Answer:

d) Metallic character decreases as you go to the right across a row in the periodic table and increases as you go down a column.

Explanation:

  • <em><u>Metallic character decreases as you move across a period in the periodic table from left to right.</u></em> This is because the attraction between valence electron and the nucleus increases, making it difficult for loss of electrons. It occurs as atoms more readily accept electrons to fill a valence shell than lose them to remove the unfilled shell.
  • On the other hand, <em><u>Metallic character increases as you move down an element group in the periodic table.</u></em> This is due to the increase in atomic radius as the number of energy levels increases.
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Answer: Option (d) is the correct answer.

Explanation:

According to the given situation, mass of compound will be calculated as follows.

Mass of compound = mass of flask and condensed vapor - mass of flask

                                 = 115.23 - 114.85

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Volume (V) = 255 mL = 255 \times 10^{-6} m^{3}        (as 1 ml = 10^{-6} m^{3})

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Temperature = 100^{o}C = (100 + 273) K = 373 K

Now, according to the ideal gas equation, PV = nRT

and, moles of compound n = \frac{PV}{RT}

                     = \frac{101325 \times 255 \times 10^{-6}}{8.314 \times 373}

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As, molar mass of compound = \frac{mass}{\text{no. of moles}}

                                                  = \frac{0.38}{0.008332}

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