Answer:
(a) OPTION E=4
b) option E C sp² + C p
Explanation:
DEGREE OF UNSATURATION = C -H/2 -X/2 +N/2 +1
X IS HALOGENS
5-5/2+1/2+1= 4
b) Ethene comprises of two sp2-hybridized carbon atoms (bound to each other by sigma and two atoms each with hydrogen). The remaining unhybridized carbon p orbitals form a pi bond, giving ethene reactivity
Answer:
C. trophic levels
Explanation:
Trophic levels are the feeding positions of all organisms in a specific ecosystem. There are five main trophic levels, or feeding levels.
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Habitats are the environment in which organisms live. They are not feeding levels.
Taxonomic levels are a way of classifying species. They consist of (in order) domain, kingdom, phylum, class, order, family, genus, and species. They are not feeding levels.
Cladograms are branching diagrams that show the relationship between multiplt organisms/species. It too is not a feeding level.
Thus, is answer is C.
hope this helps!
Answer: .B. 13C NMR spectra display peaks for only carbons that bear hydrogen atoms.
Explanation:
The statements that are true about 13C NMR are:
A. In 13C proton-decoupled NMR spectra, all peaks are singlets.
C 13C NMR chemical shifts occur over a greater range than 1H NMR chemical shifts.
D. 13C NMR easily differentiates between the different hybridized carbons (sp3, sp2, and sp hybridized carbons).organic-chemistry
Therefore, the option that isn't true is option B. "13C NMR spectra display peaks for only carbons that bear hydrogen atoms". This is false because 13C NMR will show every peak in the spectrum and it doesn't matter if it's only carbons that bear hydrogen atoms as everything will be shown.
The number of hydrogen atoms is twice the number of oxygen atoms in ribose.
<h3>What is Ribose?</h3>
This is a sugar and a component of the ribonucleotides from which RNA is built. It has the formula C₅H₁₀O₅.
Ribose is a carbohydrate with the formula C₅H₁₀O₅. This molecule is a pentose monosaccharide which has a linear form
. The hydroxyl groups lie on the same side in the form of Fischer Projections.
The number of hydrogen atoms is double the number of oxygen atoms. The ribose sugar is found in the RNA.
It is the genetic material which is found in some organisms that carry information from one generation to another.
Read more about Ribose here:
brainly.com/question/923091
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Answer:
5%
Explanation:
Given parameters:
Volume of original acetone before dilution = 10ml
Volume of diluted solution = 200ml
Unknown:
Percent volume of acetone in the solution = ?
Solution:
To find the percent volume of acetone in the diluted solution, use the expression below;
Percent volume of acetone = 
Insert the parameters and solve;
Percent volume of acetone =
x 100 = 5%