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Verizon [17]
3 years ago
12

What is the wavelength of a photon that will be emitted when an electron in the hydrogen atom moves from n

Chemistry
1 answer:
tigry1 [53]3 years ago
5 0

Answer:

Use the Rydberg Equation 1/λ = R(1/n²(final) - 1/n²(initial) where R = 109,678 cm⁻¹. Substitute initial orbital number and final orbital number and solve for wavelength (λ).

Explanation:

Example:

Assume an electron transition from n = 5 to n = 2.

1/λ = 109,678cm⁻¹(1/2² - 1/5²) = 109,678(0.25 - 0.04)cm⁻¹ = 23,032cm⁻¹

λ = 1/23,032cm⁻¹ = 4.34 x 10⁻⁵cm x 10⁻²m/cm x 10⁹nm/m = 434nm

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Answer:

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100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
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The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

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Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

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3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}

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n = moles of NaCN = \frac{\text {given mass}}{\text {Molar mass}}

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x=18.62\times 10^{-5}g

Thus the number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

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