The density of properties will not increase by changing the amount of materials, but only will change if temperature changes because it is the weight <em>per cubic centimeter</em>. For example if you have 20000 grams of gold and its volume is 1040 cubic centimeters, but you also have 550 grams of gold which has a volume of 28.5 cubic centimeters the calculations prove it;
20,000/1040= 19.2 grams per cubic centimeter
as well as 550/28.5= 19.2 grams per cubic centimeter.
Answer:
3.09 atm
Explanation:
Given that:
Volume of container A = 717 mL
Pressure of container A = 2.80 atm
Volume of container B = 174 mL
Pressure of container B = 4.30 atm
Now, if the valve are being removed and the gases are allowed to mix together; then
The total final pressure can be calculated by using the formula:
Rutherford !
The so-called Rutherford experience consisted mainly of launch, against a gold plate, with a beam of particles emitted by a radioactive source. These particles whose electric charge is positive are known as alpha particles.
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Answer:
H2SO4
Explanation:
An electrolyte is a chemical compound that conducts electricity by changing into ions when melted or dissolved into a solution. An example of an electrolyte is sodium chloride.
Strong acids such as sulfuric acid (H2SO4), and strong bases such as potassium hydroxide (KOH), and sodium hydroxide (NaOH) are frequently used as electrolytes due to their strong conducting abilities.
Explanation:
Knowing the pH, you know the concentration of protons:
−log[H+]=pH=3.7
[H+]=10−3.7 M
Now, since the weak (monoprotic) acid dissociates into its conjugate base and a proton, the mols of protons are equimolar with the mols of conjugate base---the protons came FROM the weak acid, so the conjugate base that forms must be equimolar with the protons given out to the solvent.
HA⇌A−+H+
Hence, [A−]=[H+] in the same solution volume. Using the equilibrium constant expression, we get:
Ka=[H+]2eq[HA]eq
Don't forget that the HA form of HA had given away protons, so the mols of protons given away to generate A− is subtracted from the mols of (protons in) HA.
=[H+]2eq[HA]i−[H+]eq
=(10−3.7M)20.02M−10−3.7M
Ka=2.0105×10−6 M
