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mihalych1998 [28]

2 years ago

5

What are the three types of symbiotic relationships?

2 answers:

krok68 [10]2 years ago

6 0

Answer: mutualism, commensalism, and parasitism

Explanation: with mutualism, both partners benefit. With commensalism, only one species benefits while the other is neither helped nor harmed. With parasitism, one organism (the parasite) gains benefits, while the other (host) suffers.

sattari [20]2 years ago

5 0

Answer:mutualism, commensalism, parasitism

Explanation: both partners benefit, only one species benefits while the other is neither helped nor harmed, one organism(the parasite) gains, while the other(host) suffers.

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SEP Analyze Data Look at the phase diagram. What is the state of matter for methanol at a temperature of −0.1°C and a pressure o

devlian [24]

If it’s a negative number and a positive it might be 1.4

8 0

2 years ago

An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for

8090 [49]

Answer: The freezing point and boiling point of the solution are $-6.6^0C$ and $101.8^0C$ respectively.

Explanation:

Depression in freezing point:

$T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of water = $0^0C$

$k_f$ = freezing point constant of water = $1.86^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_f=-6.6^0C$

Therefore,the freezing point of the solution is $-6.6^0C$

Elevation in boiling point :

$T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^0C$

$k_b$ = boiling point constant of water = $0.52^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_b=101.8^0C$

Thus the boiling point of the solution is $101.8^0C$

4 0

3 years ago

Can isotopes have different atomic numbers

Tpy6a [65]

Answer:

No

Explanation:

Atomic number represents the identity of atoms

using number of protons which is equal in isotopes.

6 0

3 years ago

Which 2 elements make up the most mass in the human body?

liq [111]

Answer: Oxygen and Carbon

Explanation:

8 0

3 years ago

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Which statement describes climate and not weather?

sasho [114]

I would answer B!! But your guess is as good as mine!!

3 0

2 years ago

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