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2 years ago

What evidence exists to support the idea that the composition of ocean water includes dissolved oxygen?

Chemistry

2 answers:

blondinia [14]2 years ago

6 0

Answer:

The evidence that exists to support the idea that the composition of ocean water includes dissolved oxygen is that all water has oxygen in it.

Explanation:

Setler79 [48]2 years ago

5 0

Answer:

Fish get oxygen from water through their gills - they require oxygen to survive, so they have to be getting it from the water.

Explanation:

The concentration of dissolved oxygen and carbon dioxide are very important for marine life forms. Although both oxygen and carbon dioxide are a gas when outside the water, they dissolve to a certain extent in liquid seawater. Dissolved oxygen is what animals with gills use for respiration (their gills extract the dissolved oxygen from the water flowing over the gill filaments).

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Delvig [45]

Answer:

First

divide each element by its Molecular Mass to get their respective moles

Then Divide through by the lowest of the moles

You'll have the ratio of Carbon Hydrogen and Oxygen to be

C2H3O

Given Molecular Mass=184.27

C2H3On=184.27

n(12x2 + 1x3 + 16) =184.27

Evaluating this... You'll have n=4.3

Pls check if you assigned the correct value to each element

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2 years ago

Find the momentum of 5 kg bowling ball at 10 m/s.

leva [86]

30 kg m/s

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3 years ago

Mixed Practice:

AveGali [126]

Given

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Molar mass of NO - 30.01g/mol

No of moles of NO = Given mass/Molar mass

No of moles of NO = 824/30.01= 27.45 mole

Hence 27.5 moles of NO are formed!

4 0

2 years ago

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QveST [7]

Answer:

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1 year ago

A helium balloon has a pressure of 0.2 kPa and a volume of 15 L. If the pressure increases to 0.5 kPa, what volume will the ball

Alex17521 [72]

Answer:

6.0 L

Explanation:

For this question, we can use

P1×V1= P2 × V2

where

P1 (initial pressure)= 0.2 kPa

V1 (initial volume)= 15L

P2 (final pressure)= 0.5 kPa

V2(final volume)= ?

Since we are trying to find final volume, we can rearrange the equation to make V2 the subject.

V2= (P1 × V1)/ P2

V2= (0.2 ×15)/0.5

V2 =6 L

7 0

2 years ago