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3 years ago

What evidence exists to support the idea that the composition of ocean water includes dissolved oxygen?

Chemistry

2 answers:

blondinia [14]3 years ago

6 0

Answer:

The evidence that exists to support the idea that the composition of ocean water includes dissolved oxygen is that all water has oxygen in it.

Explanation:

Setler79 [48]3 years ago

5 0

Answer:

Fish get oxygen from water through their gills - they require oxygen to survive, so they have to be getting it from the water.

Explanation:

The concentration of dissolved oxygen and carbon dioxide are very important for marine life forms. Although both oxygen and carbon dioxide are a gas when outside the water, they dissolve to a certain extent in liquid seawater. Dissolved oxygen is what animals with gills use for respiration (their gills extract the dissolved oxygen from the water flowing over the gill filaments).

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What is the mass in grams of 1.22 x 10 to the 24th power atoms of gallium?

UNO [17]

Answer:

4355

Explanation:

bexause of 25 power

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3 years ago

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A gas has a volume of 62.65 L at STP. At what temperature (in oC) would the volume of the gas be 78.31 L at a pressure of 612.0

masha68 [24]

Answer:

1.788 C DEGREES

Explanation:

STP is 1 atm at 273.15 K

P1V1/T1 = P2V2/T2

(1)(62.65) / (273.15) = (612/760)(78.31)/T2

T2 = 274.93 K = 1.788 C

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2 years ago

15 The picture shows Earth’s rotation. Which pattern listed below is caused by Earth’s rotation? A Water cycle processes B Lengt

Kruka [31]

Answer:

jayfeather friend me

Explanation:

Hence it is quite important to understand and learn the processes of the water cycle.

Step 1: Evaporation. The water cycle starts with evaporation. ...

Step 2: Condensation. ...

Step 3: Sublimation. ...

Step 4: Precipitation. ...

Step 5: Transpiration. ...

Step 6: Runoff. ...

Step 7: Infiltration.

5 0

3 years ago

Elements x and y form 2 binary compounds. In the first 14.0 g of x combines with 3.0 g of y. In the second, 7.00 g of x combine

Roman55 [17]

second compound

Let molar mass of x is = X

Let molar mass of y is = Y

Moles of x in second compound = Mass / molar mass = 7 / X

Moles of y in second compound = Mass / molar mass = 4.5 / Y

For second compound

7 / X : 4.5/ Y = 1:1

Therefore

X / Y = 7/4.5

Y / X = 4.5/ 7

The mass of x in first compound = 14g

moles of x in first compound = 14/X

Mass of y in first compound = 3

moles of y in first compound = 3 / Y

14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1

Thus molar ratio in first compound = moles of x / Moles of y = 3:2

Formula = x3y

6 0

3 years ago

The concentration of a saturated BaCl2 solution is 1.75 M (mol/liter) and the concentration of a saturated Na2SO4 solution is 2.

Kitty [74]

Answer:

a) The theoretical yield is 408.45g of $BaSO_{4}$

b) Percent yield = $\frac{realyield}{408.45g}*100$

Explanation:

1. First determine the numer of moles of $BaCl_{2}$ and $Na_{2}SO_{4}$ .

Molarity is expressed as:

M= $\frac{molessolute}{Lsolution}$

- For the $BaCl_{2}$

M= $\frac{1.75molesBaCl_{2}}{1Lsolution}$

Therefore there are 1.75 moles of $BaCl_{2}$

- For the $Na_{2}SO_{4}$

M= $\frac{2.0moles[tex]Na_{2}SO_{4}$ }{1Lsolution}[/tex]

Therefore there are 2.0 moles of $Na_{2}SO_{4}$

2. Write the balanced chemical equation for the synthesis of the barium white pigment, $BaSO_{4}$ :

$BaCl_{2}+Na_{2}SO_{4}=BaSO_{4}+2NaCl$

3. Determine the limiting reagent.

To determine the limiting reagent divide the number of moles by the stoichiometric coefficient of each compound:

- For the $BaCl_{2}$ :

$\frac{1.75}{1}=1.75$

- For the $Na_{2}SO_{4}$ :

$\frac{2.0}{1}=2.0$

As the $BaCl_{2}$ is the smalles quantity, this is the limiting reagent.

4. Calculate the mass in grams of the barium white pigment produced from the limiting reagent.

$1.75molesBaCl_{2}*\frac{1molBaSO_{4}}{1molBaCl_{2}}*\frac{233.4gBaSO_{4}}{1molBaSO_{4}}=408.45gBaSO_{4}$

5. The percent yield for your synthesis of the barium white pigment will be calculated using the following equation:

Percent yield = $\frac{realyield}{theoreticalyield}*100$

Percent yield = $\frac{realyield}{408.45g}*100$

The real yield is the quantity of barium white pigment you obtained in the laboratory.

7 0

3 years ago