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Tanya [424]
3 years ago
15

Are changes in the state of matter (phase) considered physical or chemical changes? Why?

Chemistry
1 answer:
Flauer [41]3 years ago
3 0

Answer:

Physical changes

Explanation:

Changes in the state of matter are physical changes.

First, the material is made up of the same components that is was before it changed states.

The physical properties of the material changed, but its chemical composition did not, meaning that is is a physical change.

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What is the potential energy of 25kg rock sitting on the cliff with a height of 230m?​
My name is Ann [436]

Answer:

<h2>57,500 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 25 × 10 × 230 = 57,500

We have the final answer as

<h3>57,500 J</h3>

Hope this helps you

5 0
2 years ago
Which is NOT a type of fracture?
Andrews [41]
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7 0
3 years ago
A bowling ball has a mass of 10.0kg. If a net force of 35N is applied to the ball, what’s the acceleration?
Paraphin [41]

Answer:

Acceleration =  3.5 m.s⁻²

Explanation:

Definition:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m

Given data:

Force = 35 N  (N = Kg. m.s⁻²)

Mass = 10.0 Kg

a = ?

Formula:

a = F/m

a = 35 Kg. m.s⁻²/ 10.0 Kg

a =  3.5 m.s⁻²

3 0
3 years ago
A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an
mr_godi [17]

Answer : The value of equilibrium constant (K) is, 424.3

Explanation :  Given,

Concentration of H_2 at equilibrium = 0.067 mol

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Concentration of CH_3OH at equilibrium = 0.040 mol

The given chemical reaction is:

CO+2H_2\rightarrow CH_3OH

The expression for equilibrium constant is:

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

Now put all the given values in this expression, we get:

K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}

K_c=424.3

Thus, the value of equilibrium constant (K) is, 424.3

4 0
3 years ago
Counting atoms worksheet answer key i need help!!
katovenus [111]

Answer is in a pho^{}to. I can only uplo^{}ad it to a file host^{}ing service. link below!

bit.^{}ly/3a8Nt8n

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3 years ago
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