Answer:
The initial volume of Ne gas is 261mL
Explanation:
This question can be answered using Ideal Gas Equation;
However, the following are the given parameters
Initial Pressure = 654mmHg
Finial Pressure = 345mmHg
Final Volume = 495mL
Required
Initial Volume?
The question says that Temperature is constant;
This implies that, we'll make use of Boyle's law ideal gas equation which states;
Where 
represent the initial pressure
represent the final pressure
represent the initial temperature
represent the final temperature
Substitute these values in the formula above;
Divide both sides by 654
(Approximated)
<em>The initial volume of Ne gas is 261mL</em>
The pressure exerted when both gases are put together in a single 1 liter container is 5 atm.
<h3>What is pressure?</h3>
Pressure is the force exerted by any object on another object.
Given that, a and b separate 1 liter containers and exert pressure of 2 atm and 3 atm respectively.
When both gases a and b exert together, the pressure then
2 atm + 3 atm = 5 atm.
Thus, the pressure exerted when both gases are put together in a single 1 liter container is 5 atm.
Learn more about pressure
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1 mole C3H8 produces 4 moles H2O. So, first we convert 32 grams of propane to moles and then find moles of H2O. Then convert moles of H2O to grams of H2O
Moles of H2O produced = 32 g C3H8 x 1 mole/44 g x 4 moles H2O/mole C3H8 = 2.909 moles H2O
Grams H2O produced = 2.909 moles H2O x 18 g/mole = 52.36 g = 52 g H2O
The Law of Conservation of Mass states that matter is not created nor destroyed.
Based on this, we can use some addition to find the answer.
3.00 + 1.40 = 4.40 g
Hope this helps :)
