7. How many grams are there in 2.5 moles of silver?
2 answers:
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Explanation:
Let us assume that the concentration of [ and
is equal to x. Then expression for
for the given reaction is as follows.
Now, we will take square root on both the sides as follows.
M
Thus, we can conclude that the concentration in neutral water at this temperature is
M.
Answer:
The yield of the product in gram is
Explanation:
Given that:
the molecular mass weight of the product = 96.2 g/mol
the molecular mass of the reagent (3S)-2,2,-dibromo-3,4-dimethylpentane is 257.997 g
given that the millimoles of the reagent = 2,7 millimoles =
We know that:
Number of moles = mass/molar mass
Then:
mass = 0.697
Theoretical yield = (number of moles of the product/ number of moles of reactant) × 100
i.e
Theoretical yield =
where;
and
Theoretical yield =
Given that the theoretical yield = 100%
Then:
where,
= derived weight of the product
the molecular mass of the derived product
the molecular mass of the reagent
= weight in a gram of the reagent