at 2.304×10⁹m the electric field magnitude equal to 2.50 nc.
electric field due to a long uniformly charged wire is given as,
E= 2kλ/r
where,
k is a constant
λ is uniform charge density
r is the distance from the wire
λ = 3.20 × 10⁻¹⁰C/m
k= 9×10⁹
therefore r = 2kλ/E
on substituting value we get,
r= 2.304×10⁹m
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Answer:
A) Battery
Explanation:
A Battery because it holds lithium whatever stuff and we can use to power our electronics (Chemical -> electrical)
Hair dryers (electrical-> kinetic)
Television ( Electrical -> ???)
Hydroelectric plant ( Kinetic -> electrical)
Answer:
0.52378
Explanation:
V = Velocity = 50 m/s
r = Radius = 1.25 m
I = Moment of inertia = 110 kgm²
N = Weight supported by wheels = 14000 N
The angular velocity


Frictional force is given by

The coefficient of friction is given by

The coefficient of friction is 0.52378
Answer:
The critical angle for light is 41.81 degrees.
Explanation:
We have, light is propagating from a material with index of refraction of 1.50 to a material with index of refraction of 1. It is required to find the critical angle for light. It is angle for which the angle of refraction is equal to 90 degrees. It is given by :

So, the critical angle for light is 41.81 degrees.