Answer:
W = 0 J
Explanation:
The amount of work done by gas at constant pressure is given by the following formula:
where,
W = Work done by the gas
P = Pressure of the gas
ΔV = Change in the volume of the gas
Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:
<u>W = 0 J</u>
E = hf
E : photon energy
h : Plank's constant 6.63×10^-34
f : frequency
Hope it helped!
The correct answer to the question is D) 6 joules.
EXPLANATION:
As per the question, four measurements are given i.e 24 m/s, 60 mg, 15 L and 6 J.
We are asked to determine the measurement which corresponds to energy.
Energy is measured in various units like joule, erg, electron volt etc.
Joule is the unit of energy in S.I system.
Hence, the correct measurement which corresponds to energy is 6 joules.
All other measurements like 24 m/s, 60 mg and 15 L are not the measurements of energy. These are the measurements of speed, mass and volume respectively.
Given that.
F=3•i+4•j
And it from point (0,0)m to (5,6)m
dx=final position - initial position
dx=(5,6)-(0,0)
dx=(5,6)m
dx=5•i +6•j
Work done by the force is give by
W = F•dx
W=F•dx
Note that i•i=j•j=1 and i•j=j•i=0
Then,
W=(3i+4j)•(5i+6j)
Therefore,
W=3i•(5i+6j)+4j•(5i+6j)
W=15i•i+18i•j+20j•i+24j•j
W=15+0+0+24
W=39J
Then the work done by the force is 39 Joules
