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Marina CMI [18]
3 years ago
6

For which of these questions could a testable hypothesis be developed? Check all that apply. A. Are gases better than solids? B.

Do different liquids freeze at the same rate? C. Do cookies taste better when they are baked in a gas oven or in an electric oven? D. Does temperature affect the strength of a magnet? E. Does the color of water affect how quickly it evaporates?
Physics
2 answers:
Shalnov [3]3 years ago
7 0

Testable hypotheses could be developed for questions  <em>B,  D,  and  E</em> .

The main problem with  A  and  C  is the word "better".  This is a rubber word.  It means different things to different people, and it can mean different things to the same person at different times.  It's always a matter of opinion, it has no unique units of measure, and there is no concrete way to measure it.  Not good for developing a testable hypothesis.

OlgaM077 [116]3 years ago
3 0

Answer:

B, D, E

Explanation:

When determining if something could have a testable hypothesis you have to determine if you could test the hypothesis you come up with. An example hypothesis could be for B saying If I put different liquids in the freezer at the same time, then (liquid example) would freeze the fatest (or slowest) this is something you can test and can be measured by a test with data.

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soldier1979 [14.2K]

Answer:

Be pushed away from each other.

Explanation:

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3 years ago
A coil of 40 turns is wrapped around a long solenoid of cross-sectional area 7.5×10−3m2. The solenoid is 0.50 m long and has 500
defon

To solve this problem it is necessary to apply the concepts related to mutual inductance in a solenoid.

This definition is described in the following equation as,

M = \frac{\mu_0 N_1 N_2A_1}{l_1}

Where,

\mu =permeability of free space

N_1 = Number of turns in solenoid 1

N_2 = Number of turns in solenoid 2

A_1= Cross sectional area of solenoid

l = Length of the solenoid

Part A )

Our values are given as,

\mu_0 = 4\pi *10^{-7}H/m

N_1 = 500

N_2 = 40

A = 7.5*10^{-4}m^2

l = 0.5m

Substituting,

M = \frac{\mu_0 N_1 N_2A_2}{l_1}

M = \frac{(4\pi *10^{-7})(500)(40)(7.5*10^{-4})}{0.5}

M = 3.77*10^{-4}H

PART B) Considering that many of the variables remain unchanged in the second solenoid, such as the increase in the radius or magnetic field, we can conclude that mutual inducantia will appear the same.

8 0
3 years ago
When measuring an object with a ruler, the end of the object should be lined up with the _______of the ruler.
KatRina [158]
0 mark is your answer because you want to start at 0
8 0
2 years ago
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During their physics field trip to the amusement park, Leslie and Maria took a ride on the Whirligig. The Whirligig ride consist
grandymaker [24]

Answer:

a) frequency = 0.1724 Hz

b) Period = 5.8 sec

c) speed = 7.04 m/s

d) acceleration = 7.62 m/s²

Explanation:

Given that;

radius = 6.5m

time period = 5.8 sec every circle

a)  the frequency

frequency is the number of rotation in unit time

frequency = 1 / time period = 1/5.8

frequency = 0.1724 Hz

b)  the period

period is time taken in one rotation

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Period = 5.8 sec

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speed = 7.04 m/s

d) acceleration

To find the acceleration we take the linear velocity squared divided by the radius of the circle.

so

acceleration = v² / r = (7.04)² / 6.5 = 49.5616 / 6.5

acceleration = 7.62 m/s²

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