Answer:
acceleration is the rate in which your speed increase at a constant or steady rate
Explanation:
Answer:
Explanation:
Let assume that ball strikes a vertical wall in horizontal direction. The situation can be modelled by the appropriate use of the definition of Moment and Impulse Theorem, that is:
The average force acting on the ball during the collision is:
Depending on the surface area and weight, either can fall slower.
<u>Explanation:
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If you were to drop a feather and a brick off a building at the same height, the brick would reach the ground first. This is due to air resistance and how it slows the feather down compared to the brick. The surface area of the feather creates more resistance compared to its weight, therefore it hits the ground slower. It really all depends on the surface area, weight and the air resistance it creates.
If all air resistance were to be removed, then what would happen is that the two objects would fall and reach the ground at the same time. This is because the objects are in free fall, and because they are in free fall, the two objects would be falling at an acceleration of 9.81 m/s². This is true for all objects in free fall.
Answer:
"Crust" refers to a
terrestrial planet's outermost surface.
In general, the Earth's crust is divided into
older, thicker continental crust and younger, denser oceanic crust.
...
The thin, 40-kilometer (25-mile) deep crust of our planet — just
1 per cent of Earth's mass — contains all known universe existence.
Explanation:
Continental crust is thicker, 22 miles (35 km) on average and less dense than oceanic crust, which accounts for its mean surface elevation of about 3 miles (4.8 km) above that of the ocean floor (Archimedes’ principle). Continental crust is more complex than oceanic crust…
Answer:
Therefore,
The potential (in V) near its surface is 186.13 Volt.
Explanation:
Given:
Diameter of sphere,
d= 0.29 cm
Charge ,
To Find:
Electric potential , V = ?
Solution:
Electric Potential at point surface is given as,
Where,
V= Electric potential,
ε0 = permeability free space = 8.85 × 10–12 F/m
Q = Charge
r = Radius
Substituting the values we get
Therefore,
The potential (in V) near its surface is 186.13 Volt.
