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3 years ago

The data table shows the sound levels of common noise sources.

Physics

2 answers:

Monica [59]3 years ago

5 0

Answer: woodworker

Explanation: just took it

lianna [129]3 years ago

4 0

Answer:

woodworker is the correct answer

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____________ was a series of human spaceflight missions undertaken by the u.S. Devoted to the goal of landing a man on the moon

4vir4ik [10]

Answer:

The Apollo program or Project Apollo was a series of human spaceflight missions undertaken by the u.S. Devoted to the goal of landing a man on the moon and returning him to earth safely.

Explanation:

Project Apollo or Apollo program was the spaceflight program carried out by the United States of America during the years 1961-1972 using the Apollo spacecraft. This project's main goal was to land a man on the Moon and to safely return him to Earth. This goal was accomplished with the Apollo 11 moon-landing mission on July 20, 1969, when an Apollo Lunar Module (LM) landed on the Moon's surface and the astronauts Neil Armstrong and Buzz Aldrin walked on the lunar surface while Michael Collins stayed in the command and service module (CSM) in the lunar orbit. On July 24, all three astronauts landed safely on Earth.

This project included three unmanned test flights (Apollo 4 through Apollo 6) and eleven manned flights (Apollo 7 through Apollo 17). All these spaceflight missions were carried out by NASA (National Aeronautics and Space Administration) and all were launched from the Kennedy Space Center, Florida.

7 0

4 years ago

In a Young’s interference experiment, the two slits are separated by 0.150 mm and the incident light includes two wavelengths: l

dezoksy [38]

Answer:

2.52 × 10⁻² cm

Explanation:

The distance of bright fringe from the center of the screen is given by the formula

$y = \frac{m\lambda D}{d}$

Here, wavelength is λ, Distance of the screen from the slits is D, seperation between the

slits is d.

Separation between the slits, d = 0.15 mm

$= 0.15 * 10^{-3} m$

Distance of the screen from the slits = 1.40 m

We have a wavelength, λ1 = 540 nm

= $540 * 10^{-9} m$

By substituting all these values in the above equation we get

y1 = mλD/d

$y1 = m(540 \times 10^{-9} m)(1.40 m)/(0.15 \times 10^{-3} m)$

$y1 = m(5.04 * 10^{-3} m)$

We have a wavelength, λ2 = 450 nm

= $450 * 10^-9 m$

By substituting all these values in the above equation we get

$y_2 = \frac{m\lambda D}{d}$

$y_2 = m(450 * 10^{-9} m)(1.40 m)/(0.15 * 10^{-3} m)$

$y_2 = m'(4.20 * 10^{-3} m)$

According to the problem, these two distance are coincides with each other.

So,

$y_1 = y_2$

$m(5.04 * 10^{-3} m) = m'(4.20 * 10^{-3} m)$

by testing values, the above equation is satisfied only when, m = 5 and m' = 6

Then from the above we have

y1 = y2 = 0.0252 m

= 2.52 × 10⁻² cm

8 0

3 years ago

A black hole is a ________

masya89 [10]

Answer:

Answer to the question:

Explanation:

A black hole is a finite region of space within which there is a mass concentration high and dense enough to generate a gravitational field such that no material particle, not even light, can escape it.

8 0

3 years ago

A piece having a length of 4.0 cm was cut from a much longer, uniform rod. The piece has a volume of 3.0 cm3 and a mass of 24 g.

Gre4nikov [31]

Answer: 96

Explanation:

6 0

3 years ago

*8–52. Beam AB has a negligible mass and thickness, and supports the 200-kg uniform block. It is pinned at A and rests on the to

denis23 [38]

Answer:

μ₁ = 0.1048

μ₂ = 0.1375

Explanation:

Using static equation can find in both point the moment and the forces so:

∑ M = F *d , ∑ F = 0

∑ M A = 0

N₁ * 3 - 200 * 9.81 * 1.5 = 0

N₁ = 981

∑ M y = 0

N₂ + 300 * ³/₅ - 981 - 20 * 9.81 = 0

N₂ = 997.2 N

∑ M C = 0

F₁ * 1.75 - 300 * ⁴/₅ * 0.75 = 0

F₁ = 102.86

∑ M B = 0

300 * ⁴/₅ * 1 - F₂ * 1.75 = 0

F₂ = 137.14 N

The Force F1 and F2 related the coefficients of static friction

F₁ = μ₁ * N₁ ⇒ 102.86 N = μ₁ * 981 ⇒ μ₁ = 0.1048

F₂= μ₂ * N₂ ⇒ 137.14 N = μ₂ * 997 ⇒ μ₂ = 0.1375

8 0

4 years ago