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Liula [17]
3 years ago
13

How do you make molecular equations a balanced iconic.

Chemistry
2 answers:
asambeis [7]3 years ago
4 0
<span>First, write the net ionic equation for the unbalanced reaction. If you are given a word equation to balance, you'll need to be able to identify strong electrolytes, weak electrolytes and insoluble compounds. Strong electrolytes completely dissociate into their ions in water. Examples of strong electrolytes are strong acids, strong bases, and soluble salts. Weak electrolytes yield very few ions in solution, so they are represented by their molecular formula (not written as ions). Water, weak acids, and weak bases are examples of weak electrolytes. The pH of a solution can cause them to dissociate, but in those situations, you'll be presented an ionic equation, not a word problem. Insoluble compounds do not dissociate into ions, so they are represented by the molecular formula. A table is provided to help you determine whether or not a chemical is soluble, but it's a good idea to memorize the solubility rules.

</span><span><span>arate the net ionic equation into the two half-reactions. This means identifying and separating the reaction into an oxidation half-reaction and a reduction half-reaction. </span><span>For one of the half-reactions, balance the atoms except for O and H. You want the same number of atoms of each element on each side of the equation. </span><span>Repeat this with the other half-reaction. </span><span>Add H2O to balance the O atoms. Add H+ to balance the H atoms. The atoms (mass) should balance out now. </span><span>Now balance charge. Add e- (electrons) to one side of each half-reaction to balance charge. You may need to multiply the electrons the the two half-reactions to get the charge to balance out. It's fine to change coefficients as long as you change them on both sides of the equation. </span><span>Now, add the two half-reactions together. Inspect the final equation to make sure it is balanced. Electrons on both sides of the ionic equation must cancel out. </span><span>Double-check your work! Make sure there are equal numbers of each type of atom on both sides of the equation. Make sure the overall charge is the same on both sides of the ionic equation. </span><span>If the reaction takes place in a basic solution, add an equal number of OH- as you have H+ ions. Do this for both sides of the equation and combine H+ and OH- ions to form H2O. </span><span>Be sure to indicate the state of each species. Indicate solid with (s), liquid for (l), gas with (g), and aqueous solution with (aq). </span><span>Remember, a balanced net ionic equation only describes chemical species that participate in the reaction. Drop additional substances from the equation.ExampleThe net ionic equation for the reaction you get mixing 1 M HCl and 1 M NaOH is:H+(aq) + OH-(aq) → H2O(l)Even though sodium and chlorine exist in the reaction, the Cl- and Na+ ions are not written in the net ionic equation because they don't participate in the reaction.</span></span>
kicyunya [14]3 years ago
4 0
First, write the net ionic equation for the unbalanced reaction. If you are given a word equation to balance, you'll need to be able to identify strong electrolytes, weak electrolytes and insoluble compounds. Strong electrolytes completely dissociate into their ions in water. Examples of strong electrolytes are strong acids, strong bases, and soluble salts. Weak electrolytes yield very few ions in solution, so they are represented by their molecular formula (not written as ions). Water, weak acids, and weak bases are examples of weak electrolytes. The pH of a solution can cause them to dissociate, but in those situations, you'll be presented an ionic equation, not a word problem. Insoluble compounds do not dissociate into ions, so they are represented by the molecular formula. A table is provided to help you determine whether or not a chemical is soluble, but it's a good idea to memorize the solubility rules.
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The pale yellow liquid bromine pentafluoride reacts violently with water to give a mixture of bromic acid and hydrofluoric acid
topjm [15]

Answer:

The concentration of bromic acid (HBrO₃) is 0.069 moles/L

the concentration of hydrofluoric acid (HF) is 0.345 moles/L

Explanation:

(a) The balanced chemical equation for the reaction is

BrF₅ + 3H₂O → HBrO₃ + 5HF

The chemical equation is balanced

(b) To determine the concentration of each acids,

First, we will determine the different volume of the acids yielded

The solution volume is 783 mL = 0.783 L

From the balanced chemical equation,

1 mole of BrF₅ produces 1 mole of HBrO₃

Likewise, 1 mole of BrF₅ will produce 5 moles of HF

From the question,

5.40×10⁻² moles of bromine pentafluoride (BrF₅) reacted;

Hence, 5.40×10⁻² moles of HBrO₃ will be produced

and 5 × 5.40×10⁻² moles of HF will be produced.

Number of moles of HBrO₃ produced = 5.40×10⁻² moles

and Number of moles of HF produced = 2.7 × 10⁻¹ moles

From the formula,

Number of moles (n) = Concentration (C) × Volume (V)

Then,

Concentration (C) = Number of moles (n) / Volume (V)

For bromic acid (HBrO₃)

n = 5.40×10⁻² moles

Volume = 0.783L

Hence,

C = 5.40×10⁻² moles / 0.783L

C = 0.069 moles/L

This is the concentration of bromic acid (HBrO₃)

For hydrofluoric acid (HF)

n = 2.7 × 10⁻¹ moles

V = 0.783L

Hence,

C = 2.7 × 10⁻¹ moles / 0.783L

C = 0.345 moles/L

This is the concentration of hydrofluoric acid (HF)

3 0
3 years ago
A g[dsoflghdfkjlghskdjfhgkjhsdfgsjkhgkjfhsgkjgsdkfjhgsdjfhgsdfhgsdfjhgsdf
Setler79 [48]

Answer:

same

Explanation:

7 0
3 years ago
Which best describes the three general groups of elements?
Alex73 [517]

Answer:

D

Explanation:

3 0
3 years ago
(b) Ozone absorbs radiation of wavelengths 2200–2900 Å, thus protecting organisms from this radiation. Find the frequency and en
GrogVix [38]

The frequency and energy of most energetic of these photons is1.36*10^{15} Hz and 9.04*10^{-19} J respectively.

The high energy photons will have least wavelength. Taking the given less wavelength for calculation of frequency and energy of photons.

λ = 2200  Å

Also, we know, 1 Å = 10^{-10} m

So, λ = 2200*10^{-10}

λ = 2.2*10^{-7}<em> </em>m

Now, calculating frequency using the formula -

c = fλ, where c is speed of light, f is frequency and λ is wavelength.

We know, c = 3*10^{8} m/s

f = c/λ

f = \frac{3*10^{8} }{2.2*10^{-7} }

frequency = 1.36*10^{15} Hz

Now, calculating Energy through the formula -

E = hf, where E is energy, h is planck's constant and f is frequency

Value of planck's constant = 6.63*10^{-34} Js

E = 6.63*10^{-34}*1.36*10^{15}

Energy = 9.04*10^{-19} J

Thus, frequency and energy of photons is 1.36*10^{15} Hz and 9.04*10^{-19} J respectively.

Learn more about energy of photon -

brainly.com/question/15946945

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3 0
1 year ago
If anyone has done the edge acids and bases lab please help me it would be deeply appreciated
Flauer [41]

Answer:

Do you mean a biology lab

Explanation:

what's the question

7 0
3 years ago
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