Answer:
5.28 L
Explanation:
Step 1:
Data obtained from the question.
Volume of acid (Va) = 5.12L
Molarity of acid (Ma) = 2.75M
Molarity of base (Mb) = 4M
Volume of base (Vb) =.?
Step 2:
The balanced equation for the reaction
2H3PO4 + 3Mg(OH)2 → Mg3(PO4)2 + 6H2O
From the balanced equation above,
Mole ratio of the acid (nA) = 2
Mole ratio of the base (nB) = 3
Step 3:
Determination of the volume of the base.
This is illustrated below:
MaVa/MbVb = nA/nB
2.75 x 5.12 / 4 x Vb = 2/3
Cross multiply
4 x 2 x Vb = 2.75 x 5.12 x 3
Divide both side by 4 x 2
Vb = (2.75 x 5.12 x 3)/(4 x 2)
Vb = 5.28 L
Therefore, the volume of the base is 5.28 L
