I will use this conversion:
1m = 1000 mm => 1 = 1m / 1000mm
1 m = 100 cm=> 1 = 1m / 100cm
1m = 10 dm=> 1 = 1m / 10 dm
So,
B) 3.8 * 10^7 cm^3 = 3.8 * 10^7 cm^3 * [1m / 100cm]^3 = 38 m^3
C) 3.8 * 10^5 dm^3 * [1m / 10 dm]^3 = 380 m^3
D) 3.8 * 10^8 mm^3 * [1m / 1000 mm]^3 = 0.38 m^3
Now you can compare the four volumes and conclude which is the largest.
Answer: option C) 3.8 * 10^5 dm^3
Answer:
3.6 × 10²⁴ atoms of O
Explanation:
Let's consider the molecular formula of silver nitrate: AgNO₃.
We can establish the following relations:
- 1 mol of AgNO₃ has 6.02 × 10²³ molecules of AgNO₃ (Avogadro's number).
- 1 molecule of AgNO₃ has 3 atoms of oxygen.
The atoms of oxygen in 2.0 moles of silver nitrate are:
In covalent bonding electrons are shared betweed adjacent atoms.
This kind of bonding means that none of the atoms are detached from its electrons.
A molecule of compound is formed when two or more atoms are bonded through covalent bonds. The electrons shared are considered part of the valence electrons (outer energy level) of both atoms forming the covalent bonding.
Answer:
Explanation:
Mass in grams is given by
where
n = Number of molecules
= Avogadro's number = 
M = Molar mass of molecule
Molar mass of 
= 34.0147 g/mol
Mass of 
Molar mass of 
= 64.066 g/mol
Mass of 
Molar mass of 
= 48 g/mol
Mass of 
Molar mass of 
= 16.04 g/mol
Mass of 
