1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natima [27]
3 years ago
11

A car traveling at 26 m/s starts to decelerate steadily. It comes to a complete stop in 12 seconds. What is its acceleration?

Physics
1 answer:
wolverine [178]3 years ago
6 0
The answer is 2.17m/s2
You might be interested in
A bungee jumper attains a speed of 30 m/s just as the bungee cord begins to stretch. If the period of stretch is 2 s while comin
Bogdan [553]

Answer:1.53g

Explanation:

average deceleration= ?

inial velocity: u=0

final velocity: v=30m/s

time: t=2seconds

The first law of kinematics :

v=u+at

find a the subject of the formula

a=v-u/ t

a=\frac{0-30} 2

a=-30/2

a=-15m/s^{2}

The deceleration about g(acceleration due to gravity) will be:

15/9.8

1.53g

4 0
3 years ago
A nonrelativistic electron is accelerated from rest through a potential difference. After acceleration the electron has a de Bro
aleksley [76]

Answer:

Potential difference though which the electron was accelerated is 2.67\times 10^{-6}\ uV\  .

Explanation:

Given :

De Broglie wavelength , \lambda=750\ nm.

Plank's constant , h=6.626\times 10^{-34}\ J.s \ .

Charge of electron , e=-1.6\times 10^{-19}\ C.

Mass of electron , m=9.11\times 10^{-31}\ kg.m=9.11\times 10^{-31}\ kg.

We know , according to de broglie equation :

\lambda=\dfrac{h}{mv}\\\\ v=\dfrac{h}{m\lambda}\\\\v=\dfrac{6.626\times 10^{-34}\ J.s \ }{9.11\times 10^{-31}\ kg\times 750\times 10^{-9}\ m }= 969.78\ m/s .

Now , we know potential energy applied on electron will be equal to its kinetic energy .

Therefore ,

qV=\dfrac{mv^2}{2}\\\\ V=\dfrac{mv^2}{2q}

Putting all values in above equation we get ,

V=2.67\times 10^{-6}\ uV .

Hence , this is the required solution.

5 0
3 years ago
How does the nuclear charge relate to the energy of the 1s orbital?
nlexa [21]

Explanation:

Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.

The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:

Zeff = Z – S

where

Z = the number of protons in the nucleus, and

S = the shielding constant, the average number of electrons between the nucleus and the electron.

Hence, the energy required to remove an electron from the 1s orbital is the strongest.

3 0
4 years ago
If I fell asleep at 9:42 pm and woke up at 10:06 am. What was the total hours of sleep I got?
gladu [14]

Answer:

11 hours and 24 minutes total of sleep. Nice.

Explanation:

Since its going from pm to am, We have to go past 12 to 1 and go to 9 hours am, then add 42 by 24 minutes to get to the 6 minutes past 10.

#teamtrees #WAP (Water And Plant)

3 0
3 years ago
Read 2 more answers
The specific heat of soil is 0.20 kcal/kg*C and the specific heat of water is 1.00 kcal/kg*C. This means that if 1 kg of soil an
stiv31 [10]

Answer: The soil will be 4\°C warmer than the water.

Explanation:

The heat (thermal energy) absorbed can be found using the following equation:

Q=m.C.\Delta T

Where:

Q is the heat  

m is the mass of the element

C is the specific heat capacity of the material.

\Delta T is the variation in temperature

<u>In the case of soil we have:</u>

Q_{soil}=m_{soil}.C_{soil}.\Delta T_{soil} (1)

Where:

Q_{soil}=1 kcal

m_{soil}=1 kg

C_{soil}=0.2 kcal/kg \°C

\Delta T_{soil}

<u>In the case of water we have:</u>

Q_{water}=m_{water}.C_{water}.\Delta T_{water} (2)

Where:

Q_{water}=1 kcal

m_{water}=1 kg

C_{water}=1 kcal/kg \°C

\Delta T_{water}

Isolating \Delta T from both equations:

\Delta T_{soil}=\frac{Q_{soil}}{m_{soil}.C_{soil}} (3)

\Delta T_{soil}=\frac{1 kcal}{1 kg(0.2 kcal/kg \°C)}

\Delta T_{soil}=5\°C (4)

\Delta T_{water}=\frac{Q_{water}}{m_{water}.C_{water}} (5)

\Delta T_{water}=\frac{1 kcal}{1 kg(1 kcal/kg \°C)}

\Delta T_{water}=1\°C (6)

Comparing (4) and (6) we can find the soil will be 4\°C warmer than the water.

8 0
4 years ago
Other questions:
  • A typical garden hose has an inner diameter of 5/8". Let's say you connect it to a faucet and the water comes out of the hose wi
    7·1 answer
  • When a force is applied to an object for an amount of time, it is known as __________.
    10·2 answers
  • Assume a beam of light hits the boundary separating medium 1, with index of refraction n1 and medium 2, with index of refraction
    13·1 answer
  • Raindrops hitting the side windows of a car in motion often leave diagonal streaks even if there is no wind. Why? Is the explana
    5·1 answer
  • A vehicle has an initial velocity of 30 meters per second. 30 seconds later, it is traveling at a velocity of 60 meters per seco
    15·1 answer
  • Why are incandescent lights fo inefficient?​
    6·1 answer
  • A ball is rolling across the floor. Why does the ball come to a stop?
    9·2 answers
  • When friction slows a sliding block___
    12·1 answer
  • Which is not poor conductor?
    12·1 answer
  • The switch must be connected in ____________ with the load and the source.
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!