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Y_Kistochka [10]
3 years ago
8

A force of 20N pushes an object of mass 5.0kg along a rough surface of 5.0N​

Physics
2 answers:
Alecsey [184]3 years ago
8 0

Answer:

No question

Explanation: Sorry

Alika [10]3 years ago
7 0

Answer:

I'm sorry, I don't think there is any answer to give seeing as no question has been asked

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A dripping water faucet steadily releases drops 1.0 s apart. As these drops fall, does the distance between them increase, decre
ololo11 [35]

Answer:

Distance between them increase

Explanation:

The position S of the water droplet can be determined  using equation of motion

S=ut+\frac{1}{2}  at^2

where u is the initial velocity which is zero here

t is time taken, a is acceleration due to gravity

the position of  first drop after time t is given by

S_{1}  =0 \times t+ \frac{1}{2} at^2=\frac{1}{2} at^2............(1)

the position of  next drop at same time is

S_{2}  =\frac{1}{2} a(t-1)^2 = \frac{1}{2} a(t^2+1-2t)............(2)

distance between them is S_{1} -S_{2}  is a(t-1)

from the above the difference will increase with the time

3 0
3 years ago
Dimension of radius of sphere​
Readme [11.4K]

Answer:

The dimension is L

Explanation:

Dimension analysis is a method of representing quantities majorly with respect to some fundamental quantities of mass (M), length (L), time (T).

A sphere has a definite volume which relates to its radius by:

V = \frac{4}{3}\pir^{3}

In this equation \pi is a dimensionless quantity, and the unit of v is m^{3}.

But, metre is a measure of length, thus it has a dimension of L.

So that,

m^{3} ≅ L^{3}

Then,

L^{3} = r^{3}

Find the cube root of both sides to have,

r = L

Therefore, the dimension of the radius of a sphere is L.

5 0
3 years ago
Light traveling in water (n = 1.33) into an unknown medium.If rhe angles if incidence and refraction are 40 degrees and 25 degre
Bess [88]
40 degreased and 25 dregrees=65 degrees‍♀️
8 0
3 years ago
Explain how to determine the volume of an irregularly shaped object such as a rock
alexira [117]
If you have no way to accurately measure all of the object's bumps and dimples, then the only way to measure its volume is by means of fluid displacement. 

-- Put some water into a graduated (marked) container, read the amount of water, drop the object into the container, and read the new volume in the container.  The volume of the object is the difference between the two readings.

-- Alternatively, stand an unmarked container in a large pan, and fill it to the brim. Slowly slowly lower the object into the unmarked container, while the pan catches the water that overflows from it.  When the object is completely down in the container, carefully remove the container from the pan, and measure the volume of the water in the pan.  It's equal to the volume of the object.
6 0
4 years ago
Mass is a measurement of
lozanna [386]
D is the amount of space object takes up
6 0
3 years ago
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