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Amanda [17]
2 years ago
8

How to solve this?. Explain the answer.

Physics
2 answers:
julsineya [31]2 years ago
8 0

The answer should be <u>28 pocketbooks</u>

<h3 />

No. of pocketbooks read this month = 41

No. of pocketbooks read last = 13 fewer than this month

Total no. of pocketbooks read last month = 41-13= *28*

<u>Therefore, Liza read 28 books last </u><u>month</u>

<u>T</u><u>h</u><u>a</u><u>n</u><u>k</u><u> </u><u>Y</u><u>o</u><u>u</u><u> </u><u />

zaharov [31]2 years ago
5 0
If she read 41 pocketbooks this month then she read last month=41-13=28
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A motorcycle moving 18.8 m/s has<br> 57800 J of KE. What is its mass?
Brums [2.3K]

Answer:

m = 327.07 kg

Explanation:

Given that,

Kinetic energy of a motorcycle, E = 57800 J

Velocity of the motorcycle, v = 18.8 m/s

We need to find the mass of the motorcycle. The kinetic energy of an object is given by :

E=\dfrac{1}{2}mv^2

m is mass

m=\dfrac{2E}{v^2}\\\\m=\dfrac{2\times 57800 }{(18.8)^2}\\\\m=327.07\ kg

So, the mass of the motorcycle is 327.07 kg.

8 0
3 years ago
after the car leaves the platform , gravity causes it to accelerate downward at a rate of 9.8 m/s2. what is the gravitational fo
alexandr1967 [171]

The gravitational force on the car is the force popularly known
as the car's "weight".  Its magnitude is

            (9.8 m/s²) times (the car's mass, in kilograms) .

The unit of this quantity is [newton] .

5 0
3 years ago
If the man falls with his knees and ankles locked, the only cushion for his fall is a 0.480 cm give in the pads of his feet. Cal
Mariulka [41]

Answer:

The average force exerted on the man by the ground therefore is 153.319.53 N

Explanation:

Given the following information

Mass of man, m = 75 kg

height of fall, h = 0.48 cm

velocity just before landing,  v = 4.43 m/s

We therefore have

The work required to break the fall is equal to the kinetic energy of motion, just before touching the ground

Work done = Energy to absorb Kinetic Energy KE = 0.5·m·v²= F·h

Where:

F = Force required to break the fall

Therefore the force, F = (0.5·m·v² )/h

= 0.5×75 kg ×(4.43 m/s)²/(0.0048 m) = 153319.53 N

The average force exerted on him by the ground is therefore

= 153319.53 N.

4 0
3 years ago
Help please I'll mark as brainliest for the first correct answer​
Alenkinab [10]

Answer:

first one i think is this. work = 1/2 kx^2 = 1/2 Fx

2nd, is 0.08 J

Explanation:

EE = ½ kx²

EE = ½ (400 N/m) (0.02 m) ²

EE = 0.08.

THIRD, Velocity of the stone is 4 m/s when it leaves catapult.

3 0
3 years ago
The graph shows position versus time for an object moving with the constant acceleration. what is the final velocity of the obje
natali 33 [55]

Answer:

  3.0 m/s

Explanation:

The equation of motion for constant acceleration (a) is ...

  x(t)=\dfrac{1}{2}at^2 +v_0t+x_0

The problem statement tells us v₀ = 1, and we read from the graph that x₀=1. We also read from the graph that x(10) = 21. Filling these values into the equation, we can find <em>a</em> and x'(10).

  21 = \dfrac{1}{2}a(10^2)+1(10)+1\\\\10=50a\qquad\text{subtract 11}\\\\a=\dfrac{1}{5}\\\\x'(t)=at+v_0\\\\x'(10)=\dfrac{1}{5}\cdot 10+1=3.0

The final velocity of the object at t=10 s is about 3.0 m/s.

_____

<em>Comment on the graph</em>

We note this graph better represents increasing acceleration than it does constant acceleration. x(2) = 3.4 per the equation. It is graphed as about 4.

8 0
3 years ago
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