Answer:
77.78 mph
Step-by-step explanation:
[1] So we know that someone is driving 350 miles and it takes / took them 4 1/2 hours. I am going to change 4 1/2 to 4.5 for the sake of making it easier.
[2] Miles per hour, is, as it says, miles per hour. Aka, 
(your time is almost always on the bottom / the y)
[3] So, that being said, to solve you will but 350 over 4.5 like this: 
which calcuates to arounddd 77.78!
(I hope this is correct, I was slightly confused by the wording. Have a nice day!)
The answer selected is the correct answer because all of the other ones are equivalent to each other.
Answer:
∠x = 13.43°
Step-by-step explanation:
area ΔABC = 1/2 ( BD x AC) = 1/2 (22 x AC) = 42
22 x AC = 84 AC = 84/22 = 42/11 = 3.82
CD = BD - BC = 22 - 6 = 16
AD² = AC² + CD² = (3.82)² + 16² = 270.59
AD = 16.45
sin ∠x = AC / AD = 3.82 / 16.45 = 0.2322
∠x = 13.43°
Answer:
(d) 71°
Step-by-step explanation:
The desired angle in the given isosceles triangle can be found a couple of ways. The Law of Cosines can be used, or the definition of the sine of an angle can be used.
<h3>Sine</h3>
Since the triangle is isosceles, the bisector of angle W is an altitude of the triangle. The hypotenuse and opposite side with respect to the divided angle are given, so we can use the sine relation.
sin(W/2) = Opposite/Hypotenuse
sin(W/2) = (35/2)/(30) = 7/12
Using the inverse sine function, we find ...
W/2 = arcsin(7/12) ≈ 35.685°
W = 2×36.684° = 71.37°
W ≈ 71°
<h3>Law of cosines</h3>
The law of cosines tells you ...
w² = u² +v² -2uv·cos(W)
Solving for W gives ...
W = arccos((u² +v² -w²)/(2uv))
W = arccos((30² +30² -35²)/(2·30·30)) = arccos(575/1800) ≈ 71.37°
W ≈ 71°
Answer:
AC ≈ 5.03
Step-by-step explanation:
We can solve the problem above using the trigonometric ratio, they are;
SOH CAH TOA
sin Ф = opposite / hypotenuse
cosФ= adjacent/ hypotenuse
tan Ф = opposite / adjacent
From the diagram above, in reference to angle B;
opposite =AC and adjacent =BC
Since we have opposite and adjacent, the best formula to use is
tanФ = opposite / adjacent
tan B = AC / BC
tan 40 = AC/ 6
Multiply both-side of the equation by 6
6× tan 40 = AC/ 6 × 6
At the right-hand side of the equation, 6 will cancel-out 6 leaving us with just AC
6×tan 40 = AC
5.034598 = AC
AC ≈ 5.03 to the nearest hundredths
